大学数电第2章部分作业答案.ppt

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1、2.2证明下列逻辑恒等式。证明：证明：用对偶定理Evaluationonly.CreatedwithAspose.Slidesfor.NET3.5ClientProfile5.2.0.0.Copyright2004-2011AsposePtyLtd.Evaluationonly.CreatedwithAspose.Slidesfor.NET3.5ClientProfile5.2.0.0.Copyright2004-2011AsposePtyLtd.2.3已知逻辑函数Y1和Y2的真值表，试写出Y1和Y2的逻辑函数式。ABCDY20000000011001010011001001010100110

2、0011111000110010101001011111000110111110111110Evaluationonly.CreatedwithAspose.Slidesfor.NET3.5ClientProfile5.2.0.0.Copyright2004-2011AsposePtyLtd.2.7写出图P2.7（a）、（b）所示电路的输出逻辑函数式。Evaluationonly.CreatedwithAspose.Slidesfor.NET3.5ClientProfile5.2.0.0.Copyright2004-2011AsposePtyLtd.2.10将下列各函数式化为最小项之和的形式E

3、valuationonly.CreatedwithAspose.Slidesfor.NET3.5ClientProfile5.2.0.0.Copyright2004-2011AsposePtyLtd.2.15用逻辑代数的基本公式和常用公式将下列逻辑函数化为最简与或形式。Evaluationonly.CreatedwithAspose.Slidesfor.NET3.5ClientProfile5.2.0.0.Copyright2004-2011AsposePtyLtd.Evaluationonly.CreatedwithAspose.Slidesfor.NET3.5ClientProfile5.

4、2.0.0.Copyright2004-2011AsposePtyLtd.Evaluationonly.CreatedwithAspose.Slidesfor.NET3.5ClientProfile5.2.0.0.Copyright2004-2011AsposePtyLtd.Evaluationonly.CreatedwithAspose.Slidesfor.NET3.5ClientProfile5.2.0.0.Copyright2004-2011AsposePtyLtd.ABCY0100011110100111002.18用卡诺图化简法将下列函数化为最简与或形式。Evaluationonly

5、.CreatedwithAspose.Slidesfor.NET3.5ClientProfile5.2.0.0.Copyright2004-2011AsposePtyLtd.ABCDY00011110000111101011111110111111Evaluationonly.CreatedwithAspose.Slidesfor.NET3.5ClientProfile5.2.0.0.Copyright2004-2011AsposePtyLtd.ABCY010001111011011101ABCY010001111011011101Evaluationonly.CreatedwithAspos

6、e.Slidesfor.NET3.5ClientProfile5.2.0.0.Copyright2004-2011AsposePtyLtd.ABCDY00011110000111101001110101101001Evaluationonly.CreatedwithAspose.Slidesfor.NET3.5ClientProfile5.2.0.0.Copyright2004-2011AsposePtyLtd.2.20写出图P2.20中各逻辑图的逻辑函数式，并化简为最简与或形式。Evaluationonly.CreatedwithAspose.Slidesfor.NET3.5ClientPr

7、ofile5.2.0.0.Copyright2004-2011AsposePtyLtd.2.22将下列具有约束项的逻辑函数化为最简与或形式。给定约束条件为：ABCDY300011110000111101X0X1XXXX10011X0Evaluationonly.CreatedwithAspose.Slidesfor.NET3.5ClientProfile5.2.0.0.Copyright2004-