c语言平时练习小例子.doc

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1、给一个不多于4位的正整数，求出它是几位数，逆序打印出各位数字#includevoidmain(){intx,a,b,c,d;scanf("%d",&x);a=x/1000;b=x%1000/100;c=x%100/10;d=x%10;if(a!=0)printf("4:%d%d%d%d",d,c,b,a);elseif(b!=0)printf("3:%d%d%d",d,c,b);elseif(c!=0)printf("2:%d%d",d,c);elseif(d!=0)printf("1:%d",d);}从10至20之间的素数，自动

2、输出（我的）#include#includevoidmain(){intx,k;for(x=10;x>=10&&x<=20;x++){for(k=2;k<=sqrt(x);k++)if(x%k==0)break;if(k>sqrt(x))printf("%d",x);}}0-9这十个数字组成多少个无重复的三位数#includevoidmain(){intx,a,b,c,num=0;for(x=100;x<=999;x++){a=x/100;b=x/10%10;c=x%10;if(a!=b&&a!=c&&b!=c)

3、{num++;printf("%5d",x);}}printf("number=%d",num);}求300内能被17整除的最大数#includevoidmain(){intx;for(x=300;x>=1;x--)if(x%17==0)break;printf("x=%d",x);}斐波那契数列#includevoidmain(){longf1=1,f2=1,f3;intk;printf("%1dt%1dt",f1,f2);for(k=3;k<=30;k++){f3=f1+f2;printf("%dt",f3);

4、f1=f2;f2=f3;}}求300以内能被17整除的所有整数，用continue#includevoidmain(){intx;for(x=1;x<=300;x++){if(x%17!=0)continue;printf("%dt",x);}}输出三角形星花#includevoidmain(){intk1,k2;for(k1=1;k1<=4;k1++){putchar('t');for(k2=1;k2<=k1;k2++)putchar('b');for(k2=1;k2<=k1*2-1;k2++)putchar('*');

5、putchar('');}}求s=2/1-3/2+5/3-8/5…求前十项的和#includevoidmain(){floats=0,f1=2,f2=1,f=1,t,n;for(n=1;n<=10;n++){s=s+f*f1/f2;f=f*(-1);t=f2;f2=f1;f1=f1+t;}printf("s=%f",s);}逆序输出任意整数#includevoidmain(){longx,y;scanf("%d",&y);while(y!=0){x=y%10;printf("%d",x);y=y/10;}}函数求和#in

6、cludevoidmain(){floatadd(float,float);floata,b,c;scanf("%f,%f",&a,&b);c=add(a,b);printf("sumis%f",c);}floatadd(floatx,floaty){floatz;z=x+y;return(z);}输入年月日输出该天在该年的天数#includeintleap(intyear){intlp;lp=(year%4==0&&year%100!=0

7、

8、year%400==0)?1:0;returnlp;}intmonth_day(int

9、year,intmonth){intd;switch(month){case1:case3:case5:case7:case8:case10:case12:d=31;break;case2:d=leap(year)?29:28;break;default:d=30;}returnd;}intdays(intyear,intmonth,intday){inti,ds=0;for(i=1;i

10、scanf