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ID:47870642
大小:1.24 MB
页数:27页
时间:2019-11-14
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1、00习题要求:1.将题目转化为MicrosoftWord文档;2.解题过程用MicrosoftWord文档,公式用公式编辑器,只交电子文档作业;3.期末考试前必须作对所有所给题目,否则不能参加期末考试,请于指定时间前交作业。第一题(2010年3月5tl前交该题作业)星期五Fig.PI.33and卩5A2-K.i-kipI.37ComputethemaximumforcePthatcanbeappliedtothefootpedal.The1/4-in.-diameterpinatBisinsingleshear,anditsworkingshearix
2、appliedZlhepraniEebkxkshewn.Deterniific山cnwxjniuinv^ilueOl〔川lhennnmilwt®."Dthi?sheiuingsugSpecilythenri^niiitionol3、tensionand12000psiincompression.(Areducedstressincompressionisspecifiedtoreducethedangerofbuckling.)Thefree-bodydiagramofhomogeneousBCinFig.(b).TheequilibriumequationareThefree-bodydiagramoftrussinFig.(c).Theequilibriumequationare48=0,16fx3+(8x+8x)b-8x36=0,a/64+16J64+16Pbd=—8.944、4(kips)(Compression)工M〃=0,SPAy-SPCE=0PcE=24(kips)(Tension)工F、.=0,匕厂0.707鎰_36+丁64:]6謚=°Pbe二11・32(kN)(Compression)ThenormalstressofamemberCE,DEandDFiscrBD=<12000(//?/in.1stressis4000psi.ThecableattachedatChasadiameterof1/8in.anda)(Compression)^BD^BDABD=0.745(in.2)-Pbe_BE'仏_二"80"<15、2000(//?/in.2)(Compression)^BEABE=0.943(in.2)_PcE_"AC£'二24000"§20000(/75/)(Tension)AceAbe_l-2(in.2)workingnormalstressof20000psi.6in.►h——2in.6in—SolutionThefree-bodydiagramofbracketinFig.(b).Theequilibriumequationare(a)工MB=0,工化=0,PBxZF.v=0,6P-2TsinlO°=0,+TcoslO°=0,-P-Tsinl0°=0,P6、=0.05788TPBx=-0-9848TPBy=0.2315TAccordingtothenormalstressesformula,wehaveATr<7=r<20000(//?/m.2)T=245.4(lb)^■x0.125m.Accordingtotheshearstressesformula,wehaveVr=—4』P;+P:ATid1T=194.1(lb)Accordingtoformula(a),wegetP=0.05788T=0.05788X194.1=11,2(lb)4M.98482+0.23152^和例加.2)7ix0.252in.7、2第二题(2010年3刀10日前交该题作业)星期三2-40Ihesquareekmcn:of:1疋shir-nsrrnin:..入務屮口讪工ih^tI,delerininellienonruilstnuiiNofthedmgimiik.ItitndHD.:■严一Dehxfiiedi:ii2.37Aninitiallyrectangularelementofamaterialisdeformedintotheshapeshowninthefigure.Findex,ey,and丫fortheelement.5DeformedUndeformed0.2mm8、EEmoSolutionAccordingtothedefinitionoftheaxials
3、tensionand12000psiincompression.(Areducedstressincompressionisspecifiedtoreducethedangerofbuckling.)Thefree-bodydiagramofhomogeneousBCinFig.(b).TheequilibriumequationareThefree-bodydiagramoftrussinFig.(c).Theequilibriumequationare48=0,16fx3+(8x+8x)b-8x36=0,a/64+16J64+16Pbd=—8.94
4、4(kips)(Compression)工M〃=0,SPAy-SPCE=0PcE=24(kips)(Tension)工F、.=0,匕厂0.707鎰_36+丁64:]6謚=°Pbe二11・32(kN)(Compression)ThenormalstressofamemberCE,DEandDFiscrBD=<12000(//?/in.1stressis4000psi.ThecableattachedatChasadiameterof1/8in.anda)(Compression)^BD^BDABD=0.745(in.2)-Pbe_BE'仏_二"80"<1
5、2000(//?/in.2)(Compression)^BEABE=0.943(in.2)_PcE_"AC£'二24000"§20000(/75/)(Tension)AceAbe_l-2(in.2)workingnormalstressof20000psi.6in.►h——2in.6in—SolutionThefree-bodydiagramofbracketinFig.(b).Theequilibriumequationare(a)工MB=0,工化=0,PBxZF.v=0,6P-2TsinlO°=0,+TcoslO°=0,-P-Tsinl0°=0,P
6、=0.05788TPBx=-0-9848TPBy=0.2315TAccordingtothenormalstressesformula,wehaveATr<7=r<20000(//?/m.2)T=245.4(lb)^■x0.125m.Accordingtotheshearstressesformula,wehaveVr=—4』P;+P:ATid1T=194.1(lb)Accordingtoformula(a),wegetP=0.05788T=0.05788X194.1=11,2(lb)4M.98482+0.23152^和例加.2)7ix0.252in.
7、2第二题(2010年3刀10日前交该题作业)星期三2-40Ihesquareekmcn:of:1疋shir-nsrrnin:..入務屮口讪工ih^tI,delerininellienonruilstnuiiNofthedmgimiik.ItitndHD.:■严一Dehxfiiedi:ii2.37Aninitiallyrectangularelementofamaterialisdeformedintotheshapeshowninthefigure.Findex,ey,and丫fortheelement.5DeformedUndeformed0.2mm
8、EEmoSolutionAccordingtothedefinitionoftheaxials
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