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时间:2020-01-11
《电气照明试题及答案》由会员上传分享,免费在线阅读,更多相关内容在行业资料-天天文库。
1、···········································································································装订线··································································································山东建筑大学试卷共3页第3页一、填空题(每空1分,共15分)1.在明视觉条件下,人眼通常对555nm的色光最敏感。2
2、.描述光源发光能力的度量单位是,描述被照面上光强弱的度量单位是。3.有色彩的表面在与它色彩相同的光谱区域内,光谱反射系数。4.若视场内的亮度发生明暗急剧变化时,人眼因不能很快适应会造成视力下降,必要时应设置的过渡照明。5.红光的色温比蓝光,因此红光往往给人以的感觉。6.气体放电光源的启动次数对其有很大影响,故在需要频繁启动的场所一般不使用。7.灯具的距高比是之间的距离s与灯具到的高度h之比。灯具的最大允许距高比是根据确定的。为了获得均匀的照度,灯具的实际距高比应其最大允许距高比。8.Ⅰ类灯具除依靠基本绝缘防触电外,可能触及的导
3、电部件要与线连接。9.灯具与插座应配电,在个别情况下,灯具与插座可以同一回路配电,此时插座数量不应超过个(组)。二、单选题(每小题2分,共20分)得分阅卷人五、计算题(共30分)1.某电梯厅顶上装设有嵌入式紧凑型18W(Φ=1200lm)荧光灯具6盏(图1),灯具的光强分布如下表。若厅高2.4m,维护系数K=0.75,试计算电梯厅地面中心一点A的水平照度EA。(14分)θ(°)2025303540455055Iθ(cd)193191189184175163147125提示:①只计算直射照度;②Iθ值按接近表中的给定值选取;③表
4、中Iθ值是以光源光通量为1000lm测定的。···········································································································装订线··································································································山东建筑大学试卷共3页第3页至学年第学期照明工程(本科)试卷卷适用专业:
5、电气工程与自动化、电子信息工程考试形式:开卷考试时间90分钟题号一二三四五总分分数1520201530100一、填空题(每空1分,共15分)1.黄绿2.光通量照度3.最大4.明暗适应5.低温暖6.(使用)寿命7.相邻灯具中心工作面(参考平面)1/2照度角≤(小于或等于)8.保护导线(地线)9.分回路5二、单选题(每小题2分,共20分)1.B;2.B;3.D;4.B;5.B;6.C;7.C;8.D;9.C;10.D。三、多选题(每小题2分,共20分;答案正确给满分,答案正确给满分,错选、多选、少选均不得分)1.AD;2.ABC;
6、3.BCD;4.ABD;5.ABC;6.ABD;7.ABCD;8.AB;9.ABD;10.ABC。四、判断题(每题1分,共15分)1.√;2.×;3.×;4.√;5.√;6.×;7.√;8.×;9.×;10.√;11.√;12.√;13.×;14.√;15.√。五、计算题(共30分)1.(14分)按点光源水平照度计算公式计算:由于Eh1=Eh3=Eh4=Eh6,Eh2=Eh5,故先计算Eh1和Eh2,然后求和EA。已知:计算高度h=2.4m,维护系数K=0.75,光源光通量Φ=1200lm。(1)光源1产生的水平照度Eh16分
7、光源1在水平面的投影点至计算点的距离光源1至计算点的距离由表知:θ=33.3°时,若按接近表中给定值选取,则Iθ1=184cd,则(2)光源2产生的水平照度Eh26分光源2在水平面的投影点至计算点的距离d2=0.7m光源2至计算点的距离由表知:θ=16.3°时,若按接近表中给定值选取,则Iθ2=193cd,则(3)6盏灯在A点产生的实际照度EA2分2.(6分)由于供电线路的cosj≈1,故可用负荷距法校验电压损失:已知:负荷P=20kW,l=400m,则总负荷距M:·······························
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