数字信号处理英文版第二版蔡坤宝部分习题答案

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1、AppendixFAnswersToPartialProblemsAnswerstoPartialProblemsinChapter2/?=-!•32*/122.2yW=0,2-0,23Ax(n)=<1,2.42.8n>-<-<-2n=-2；Vx(n)=■<］、刃+2"u,(1)Periodic.N=200;(2)Periodic.N=2;(3)Periodic.TV=14;(4)Nonperiodic.(l)For(2)For/?()-(3)For_0〃+l一刃occ—Pa(

2、n一«o+1),_bnNa",yM=02.9y(z?)=<1-a1小•,n<0an(-a)2.10(1)Unstable,causal,linear,time-invariantanddynamic;(2)Stable,causal,nonlinear,time-invariantandmcmorylcss;(3)Stable,causal,linear,time-varyingandmemoryless;(4)Unstable,causal,linear,time-varyinganddynam

3、ic;(5)Stableforboundedg(r),causal,linear,time-varyingandmemoryless;(6)Stable・Ifn()>0ythenthesystemiscausal.Itislinearandtime-invariant.IfH0,thesystemisdynamic;(7)Stable,causal,nonlinear,time-invariantandmemoryless.(12.12y(n)=8—-81(2丿2.11ySs(n)=(-l)z,(y~j~)•u(n)•h(n)=-c>W+

4、22.14(1)⑵y(H)=ew(n)；u(n)・AnswerstoPartialProblemsinChapter331U)心心⑵xu)=7T^Jd<1/2;3.2(1)X(z)=—一—,kl>l；[z2-2zCOSft>0+1]2⑵x⑵★讥os0f仙-0)十“.Z2-2^rcosft>0+r23.3(1)ROC1:lzl>3/4;ROC2:l/2

5、llows:FigureF3.3⑶ForIzl>3/4,•4)・「1+J—J—13人丿2丿u(n)•辽=(刘刃X：9=(o")XSP((D“)X(0“)XJ—=(<^)A-(mif9)X=(mt*)/{乙乙3+訓IIG)p⑵(l)O「£(8)（厶）(l一"一”7—(I-5•(i-u-)n丄£丿uJExpUSA1L7:ep(W-o)M)H(oM)XJ〒=(“")/<：(o”a)H(叫“X=(哄巧人：(砒-刃X=：(耐？)X=(“")/{££1一+8“:("”7乙一"(g)(t)(£)(I)t(w)w认£丿厶yjd+妨一=（"找•(j+u)n

6、【+"(I)（9）Z/£2)£/、严十”7v1/1(屮)-I寻+t(I-W-)WI+w(^)=(W)X(乙)-一(必=(")x八I丿(IWU(V:(u)ni(I-u)n[Yz=(")*UI丿D+(“)£--八I丿VIt(I-w-)w（£）(I)9£=(”)x（£）厶+(")08=(映JOJ9爼乙=(")*'口/£>

7、2

8、>乙/1」oh(2)「X(e>W=4/r;J-zr(3)「IX(刃少)卩de=28/r;V、P7,dX(eJM)19f…(4)II12dco=316-t.—dco3.11yss(/?)=2逅sin彳(/?+1).3.12(

9、1)H(z)z2-z-(2)Thepole-zeroplotofH(z)withitsROCisshownasfollows:(4)Thesystemisunstable,becausetheROCdoesnotincludetheunitcircleinthez-planc.Ifwcwanttoobtainastablesystem,theROCshouldbeselectedas1-a/5.,1+V5<1zl<.22Thecorrespondingimpulseresponseis3.13(1)7})=0.05$,Qo=40ttrad

10、;00(3)ThesampledsequenceisN=5.(2)xs(r)=工cos(0.8m+号)3(/-0.02m);n=-co厶x(h)=cos(0.8^+y)andit