材料力学作业及练习题参考答案(4章)

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1、Evaluationonly.CreatedwithAspose.Slidesfor.NET3.5ClientProfile5.2.0.0.Copyright2004-2011AsposePtyLtd.Evaluationonly.CreatedwithAspose.Slidesfor.NET3.5ClientProfile5.2.0.0.Copyright2004-2011AsposePtyLtd.Evaluationonly.CreatedwithAspose.Slidesfor.NET3.5ClientProf

2、ile5.2.0.0.Copyright2004-2011AsposePtyLtd.Evaluationonly.CreatedwithAspose.Slidesfor.NET3.5ClientProfile5.2.0.0.Copyright2004-2011AsposePtyLtd.（0＜x≤2）(1)（2≤x＜4）(3)Evaluationonly.CreatedwithAspose.Slidesfor.NET3.5ClientProfile5.2.0.0.Copyright2004-2011AsposePtyL

3、td.Evaluationonly.CreatedwithAspose.Slidesfor.NET3.5ClientProfile5.2.0.0.Copyright2004-2011AsposePtyLtd.ABC0.2mMeFBFA0.1m解：⑴求支座反力：设支座反力FA、FB皆向上，以整个梁为研究对象。由∑MB＝0：Me－FA×0.2＝0得：FA＝Me/0.2＝10/0.2＝50N由∑Fy＝0：FA＋FB＝0，得：FB＝－50N习题4-2（h）(a)⑵列剪力方程和弯矩方程，AB段：以A为坐标原点，x轴水平向右为

4、正，FS＝FA＝50N（0＜x＜0.2）(1)M＝FA·x＝50xNm（0≤x≤0.2）(2)BC段：以C为坐标原点，x2轴水平向左为正，FS＝0（0≤x2＜0.1）(3)M＝Me＝10Nm（0＜x2≤0.1）(4)⑶作剪力图和弯矩图：由(1)式和(3)式知，AB段和BC段剪力均为常数，剪力图如图(b)示。由(2)式知，AB段的弯矩图为一直线，在x＝0处：M＝0；在x＝0.2处：M＝50×0.2＝10Nm由(4)式知，BC段的弯矩为一常数，M＝10Nm作弯矩图如图(c)示。(c)M(x)图10Nm(b)FS

5、(x)图50NEvaluationonly.CreatedwithAspose.Slidesfor.NET3.5ClientProfile5.2.0.0.Copyright2004-2011AsposePtyLtd.Evaluationonly.CreatedwithAspose.Slidesfor.NET3.5ClientProfile5.2.0.0.Copyright2004-2011AsposePtyLtd.Evaluationonly.CreatedwithAspose.Slidesfor.NET3.5Cli

6、entProfile5.2.0.0.Copyright2004-2011AsposePtyLtd.Evaluationonly.CreatedwithAspose.Slidesfor.NET3.5ClientProfile5.2.0.0.Copyright2004-2011AsposePtyLtd.Evaluationonly.CreatedwithAspose.Slidesfor.NET3.5ClientProfile5.2.0.0.Copyright2004-2011AsposePtyLtd.Evaluation

7、only.CreatedwithAspose.Slidesfor.NET3.5ClientProfile5.2.0.0.Copyright2004-2011AsposePtyLtd.