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1、作业习题解答第二章燃烧与大气污染2.1解：lkg燃汕含:重量（g）摩尔数（g）需氧数（g）C85571.2571.25H113-2.555.2527.625S100.31250.3125H2O22.51.250N元素忽略。1）理论需氧量71.25+27.625+0.3125=99.1875mol/kg设干空气O2：2体积比为1：3.78,则理论空气量99.1875X4.78=474.12mol/kg重汕。即474.12X22.4/1000=10.62m3N/kg重油。烟气组成为CO271.25mol,H2O55.25+11.25=56.50mol,SO20.1325mol,N23.78
2、X99.1875=374.93moL理论烟气量71.25+56.50+0.3125+374.93=502.99mol/kg重油。即502.99X22.4/1000=11.27m3N/kg重汕。2）干烟气量为502.99-56.50=446.49mol/kg重油。03125SO.白分比浓度为——-x100%=0.07%,「446.497125空气燃烧时CO?存在最大浓度一xlOO%=15.96%o446.493）过剩空气为10%时，所需空气量为1」X10.62=1l&mVkg垂油,产牛烟气量为11.267+0.1X10.62=12.33m3N/kg重油。2.2解:相对于碳元索作如卜计算:
3、%（质量）mol/100g煤mol/mol碳C65.75.4751H3.23.20.584S1.70.0530.01002.30.0720.013灰分18.13.306g/mol碳水分9.01.644g/mol碳故煤的组成为CH（）.584S（）.o1（）0（）.o13»燃料的摩尔质量（包括灰分和水分）为黑=18.26讪曲燃烧方程式为CH()5845()()
4、()0()()]3++3.78NJ—C09+0.292//?(?+O.OIOSO^+3.78/2A^?n=1+0.584/4+0.010-0.013/2=1.14951)理论空气量L1495x(1+3,78)x1000x22.4X
5、io~3m3/kg=6.74m3/kg18.26SO?在湿烟气屮的浓度为x!00%=0.174%0.01016441+0.292+0.010+3.78x1.1495+^—182)产生灰分的量为18.1x®^x80%=144・8g/Rg100烟气量(1+0.292+0.010+3.78X1.1495+1.644/18)X1000/18.26X22.4X10~3=6.826m3/kg灰分浓度为*x1O'mg/m3=2.12X104mg/n?6.8263)需右灰右1000x1.7%""32.00xl.7x4035%=103.2Mg/t煤恥抑张354.764.78=280.54加引2.3解：按
6、燃烧lkg煤计算重量(g)摩尔数(mol)需氧数(mol)C79566.2566.25H31.12515.56257.78S60.18750.1875H2O52.8752.940设干空气中N?：Ch体积比为3.78：1,所需理论空气量为4.78X(66.25+7.78+0.1875)=354.76mol/kg煤。理论烟气量CO266.25mol,SO20-1875mobH2O15.5625+2.94=18.50mol耗氧量0.003mol00.143mol0.063mol0.0Mmol总计66.25+s8.50+0.1875+280.54=365.48mol/kg煤a1875实际烟气量
7、365.48+0.2X354.76=436.43mol/kg煤，SO2浓度为莎話x100%=0.043%。2・4解:取lmol煤气计算H2S0.002molCO20.05molCO0.285molH2(0.13-0.004)molCH40.007mol共需O20.003+0.143+0.063+0.014=0.223molo设干空气中N2：O?体积比为3.78：1,则理论干空气量为0.223X(3.78+1)=1.066mole取4=1.2,则实际干空气1.2X1.066mol=1.279mol。空气含湿量为12g/m,U
8、J含H2O0.67mol/m,14.94L/h?n。故出0
9、体积分数为1.493%。1279故实际空气量为=1.298加创o1-1.493%烟气量S02：0.002mol,C02：0.285+0.007+0.05=0.342mol,N2：0.223X3.78+0.524=1.367mol,H200.002+0.126+0.014+1.298X1.493%+0.004=0.201mol故实际烟气量0.002+0.342+1.367+0.201+0.2X1.066=2.125mol2.5解:1)N2%=1-
