自动控制原理与matlab实验

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1、1．建立如下系统的传递函数模型。G1（s）=2．建立以上系统的零极点模型。3．建立以下系统的零极点模型，并转换成多项式模型。G2(s)=4．求以上系统G1(s)，G2(s)的部分分式展开。5．分别求以上系统G1(s)，G2(s)串联、并联、反馈后的总系统的传递函数。6．将以上系统G3(s)展开成部分分式。实验过程1.>>num=[1-38.7101-71.563.1562.39];>>den=[125-315122.50311.21];>>G1=tf(num,den)Transferfunction:s^5-38.7s^4+101s^3-

2、71.5s^2+63.1s+562.4--------------------------------------------------------s^7+2s^6+5s^5-31s^4+51s^3+22.5s^2+311.22.>>G2=zpk(G1)Zero/pole/gain:(s-35.94)(s-2.959)(s+1.321)(s^2-1.118s+4.004)-----------------------------------------------------------------(s+1.501)(s^2-3.904

3、s+5.061)(s^2-0.4926s+2.517)(s^2+4.896s+16.28)3.>>z=[-0.5-6.02];>>p=[0-1.3-2.6-3.5-4.9-5.11];>>z1=[-0.5-6.02];>>k=36;>>G3=zpk(z1,p,k)Zero/pole/gain:36(s+0.5)(s+6.02)------------------------------------------s(s+1.3)(s+2.6)(s+3.5)(s+4.9)(s+5.11)>>G4=tf(G3)Transferfunction:3

4、6s^2+234.7s+108.4-------------------------------------------------------------s^6+17.41s^5+116.1s^4+367.6s^3+544.8s^2+296.2s4.G1:>>[r1,p1,k1]=residue(num,den)r1=1.0414-0.9888i1.0414+0.9888i-0.6729-0.1742i-0.6729+0.1742i-0.2215-0.5306i-0.2215+0.5306i-0.2939p1=-2.4482+3.207

5、1i-2.4482-3.2071i1.9522+1.1180i1.9522-1.1180i0.2463+1.5673i0.2463-1.5673i-1.5006k1=[]G2:>>num2=[36234.7108.4];>>den2=[117.41116.1367.6544.8296.20];>>[r2,p2,k2]=residue(num2,den2)r2=0.44333.7357-10.1326i3.7357+10.1326i-11.00282.72210.3660p2=-5.5657-4.0235+0.4264i-4.0235-0.

6、4264i-2.4935-1.30370k2=[]5.串联：>>G5=G1*G4Transferfunction:36s^7-1158s^6-5339s^5+1.694e004s^4-3567s^3+2.731e004s^2+1.388e005s+6.094e004-----------------------------------------------------------------s^13+19.41s^12+156s^11+655.9s^10+1372s^9+533.8s^8-1764s^7+6263s^6+3.229e00

7、4s^5+6.351e004s^4+1.211e005s^3+1.696e005s^2+9.218e004s并联：>>G6=G1+G4Transferfunction:s^11-21.29s^10-420.6s^9-2134s^8-2374s^7+9969s^6+2.95e004s^5+8.89e004s^4+2.307e005s^3+3.387e005s^2+2.396e005s+3.372e004-----------------------------------------------------------------s^13+

8、19.41s^12+156s^11+655.9s^10+1372s^9+533.8s^8-1764s^7+6263s^6+3.229e004s^5+6.351e004s^4+1.211e005