汽车理论编程作业123章

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1、汽车理论作业：第一章1.3选四档变速器，用MATLAB语言驱动力与行驶阻力平衡图m1=2000;m2=1800;mz=3880;g=9.81;f=0.013;n=600:1:4000;nt=0.85;r=0.367;i0=5.83;ig1=6.09;ig2=3.09;ig3=1.71;ig4=1.00;ua1=0.377*r.*n/(ig1.*i0);ua2=0.377*r.*n/(ig2.*i0);ua3=0.377*r.*n/(ig3.*i0);ua4=0.377*r.*n/(ig4.*i0);tq=-1

2、9.313+295.27*(n/1000)-165.44*(n/1000).^2+40.874*(n/1000).^3-3.8445*(n/1000).^4;ft1=tq.*ig1.*i0.*nt/r;ft2=tq.*ig2.*i0.*nt/r;ft3=tq.*ig3.*i0.*nt/r;ft4=tq.*ig4.*i0.*nt/r;fz1=mz.*g.*f+2.77*ua1.^2/21.15;%fz=Ff+Fwfz2=mz.*g.*f+2.77*ua2.^2/21.15;fz3=mz.*g.*f+2.77*u

3、a3.^2/21.15;fz4=mz.*g.*f+2.77*ua4.^2/21.15;plot(ua1,ft1,ua2,ft2,ua3,ft3,ua4,ft4,ua1,fz1,ua2,fz2,ua3,fz3,ua4,fz4);title('驱动力与行驶阻力平衡图');Xlabel('ua(km/h)');Ylabel('ft(N)');最高车速m1=2000;m2=1800;mz=3880;g=9.81;f=0.013;k=600:1:4000;n(k)=k;nt=0.85;r=0.367;i0=5.83;i

4、g1=6.09;ig2=3.09;ig3=1.71;ig4=1.00;ua1(k)=0.377*r.*n(k)/(ig1.*i0);ua2(k)=0.377*r.*n(k)/(ig2.*i0);ua3(k)=0.377*r.*n(k)/(ig3.*i0);ua4(k)=0.377*r.*n(k)/(ig4.*i0);tq(k)=-19.313+295.27*(n(k)/1000)-165.44*(n(k)/1000).^2+40.874*(n(k)/1000).^3-3.8445*(n(k)/1000).^4

5、;ft1(k)=tq(k).*ig1.*i0.*nt/r;ft2(k)=tq(k).*ig2.*i0.*nt/r;ft3(k)=tq(k).*ig3.*i0.*nt/r;ft4(k)=tq(k).*ig4.*i0.*nt/r;fz1(k)=mz.*g.*f+2.77*ua1(k).^2/21.15;%fz=Ff+Fwfz2(k)=mz.*g.*f+2.77*ua2(k).^2/21.15;fz3(k)=mz.*g.*f+2.77*ua3(k).^2/21.15;fz4(k)=mz.*g.*f+2.77*ua4

6、(k).^2/21.15;ua4=max(ua4(k))disp('汽车的最高车速=');disp(ua4);disp('km/h');得到汽车的最高车速=94.9290(km/h)最大坡度和相应的附着率k=600:1:4000;f=0.013;l=3.2;a=1.947;n(k)=knt=0.85;r=0.367;f=0.013;i0=5.83;m=3880;g=9.81;G=m.*g;CDA=2.77;If=0.218;Iw1=1.798;Iw2=3.598;ig1=6.09;ua1(k)=0.377*r

7、.*n(k)/(ig1.*i0);tq(k)=-19.313+295.27*(n(k)/1000)-165.44*(n(k)/1000).^2+40.874*(n(k)/1000).^3-3.8445*(n(k)/1000).^4;b1=1+(Iw1+Iw2)./(m.*r.^2)+(If.*ig1.^2.*i0.^2.*nt)/(m.*r.^2);ft1(k)=tq(k).*ig1.*i0.*nt/r;fw1(k)=CDA.*(ua1(k).^2)/21.15;D1(k)=(ft1(k)-fw1(k))./

8、G;i(k)=D1(k)-fi=max(i(k));q=i.*l./a;disp('汽车的最大爬坡度=');disp(i);disp('最大爬坡度相应的附着率=');disp(q);得计算结果：汽车的最大爬坡度=0.3648最大爬坡度相应的附着率=0.5995加速度倒数曲线n=600:1:4000;nt=0.85;r=0.367;f=0.013;i0=5.83;m=3880;g=9.81;G=m.*