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ID:4251099
大小:5.11 MB
页数:11页
时间:2017-11-30
《朱慈勉结构力学课后习题答案 第9章》由会员上传分享,免费在线阅读,更多相关内容在行业资料-天天文库。
1、杆端ABBABCBDBE习题固分配系数0.160.120.360.36绞支端9-2固端弯矩00045-900解:设EI=6,则iAB1,iBC1.5分配传递3.67.25.416.216.20最后弯矩3.67.25.461.2-73.80410.47BA4131.51131.50.53BMBAmBAMABmABBC4131.53i231结点ABC7.203.60EI2杆端ABBABC分配系数固端0.470.53绞支16.2K
2、Nm2顺时针方向固端弯矩-6060-300EI分配传递-7.05-14.1-15.90最后弯矩-67.0545.9-45.9011MmMmB3iBABA2ABAB2145.96067.0560EI221.15KNm2逆时针方向9-3(a)解:B为角位移节点EI设EI=8,则ii1,0.5ABBCBABCPablb324412固端弯矩M48KNmBA222l2829l1M6258KNmBC82i
3、AB1,iBC1结点力偶直接分配时不变号(b)解:设EI=9,则i3,i3BDBE结点ABC33杆端ABBABC0.36BDBE33333141分配系数铰接0.50.541BA0.16固端弯矩048-581233333141315050BC0.12分配传递0333331415512结点ABC最后弯矩0103-3121144,BABC145145(c)解:B、C为角位移结点4411,CBCD14514
4、5固端弯矩:(b)解:存在B、C角位移结点设EI=6,则iii12ABBCCD244M64KNm41AB60.5BABC41412414244CBMBA128KNm31417332BC2457M50KNmBC12固端弯矩:2245MAB80KNmMCB50KNm12M80KNmBA2MM0245BCCBM200KNmCD234061M80140KNmCD822245M100KN
5、mDC结点ABC6杆端ABBABCCBCD结点ABCD分配系数固结0.50.54/73/7杆端ABBABCCBCD滑动固端弯矩-808000-140分配系数滑动0.20.80.80.2-100-20-40-40-20固端弯矩64128-5050-20047.591.468.615.6-15.6-62.4-31.2-11.4-22.8-22.8-11.472.48144.9636.24-36.24分配传递3.256.54.914.5-14.5-58-29分配传递-0.82-1.63-1.63-0.8211.
6、623.25.8-5.80.60.452.32-2.32-9.28-4.64最后弯矩-112.2215.57-15.4866.28-66.053.70.93-0.93最后弯矩96.4295.58-95.6157.02-157.03-142.97157.02EI1则M4EIm(假设12)DC95.584S12,S9,S16,S12,S16DCDADEEBDE1291643,,,,DCDADEEDEB37373777147.97结点DEB96.42杆端DCDADE
7、EDEBBE41分配系数12/379/3716/374/73/7固结0.5CACD4141固端弯矩00-9900414(d)解:DCDE-2.57-5.14-3.86-1.93414131113133.752.815-2.5DB分配传递41413111-0.72-1.43-1.07-0.5420.230.180.310.16248MKNmDE123最后弯矩3.982.99-6.985-5-2.47固端弯矩:8MKNmED3结点ACDE
8、杆端ACCACDDCDBDEED分配系数固结0.50.54/113/114/11固结固端弯矩00000-2.672.67-5-10-10-546/3392/3369/3392/3346/33(f)解:截取对称结构为研究对象。分配传递-0.35-23/33-23/33-0.35S0.5EIAA0.1270.0960.1270.064EIS4EI最后弯矩-5.35-10.7-9.3-2.442.190.2
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