C语言真题讲解

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1、练习2、用函数实现数学表达式编写函数求2.2-│x│fun1(x)=──────+0.6x-2.2x(x-1)+4.2在main()函数中调用fun1函数#include#includedoublefun1(doublex){doubley=0.0;y=(2.2-fabs(x))/(x*(x-1)+4.2)+0.6*x-2.2;returny;}voidmain(){printf("fun1(1.66)=%.3lf",fun1(1.66));}#include#includedoublefun1(d

2、oublex){/**//**/}voidmain(){clrscr();printf("fun1(0.76)=%8.3lf",fun1(0.76));printf("fun1(3.00)=%8.3lf",fun1(3.00));printf("fun1(3.76)=%8.3lf",fun1(3.76));}#include#includedoublefun1(doublex){/**//**/}voidmain(){clrscr();printf("fun1(0.76)=%8.3lf",fun1(0.76));prin

3、tf("fun1(3.00)=%8.3lf",fun1(3.00));printf("fun1(3.76)=%8.3lf",fun1(3.76));}#include#includedoublefun1(doublex){/**//**/}voidmain(){clrscr();printf("fun1(0.76)=%8.3lf",fun1(0.76));printf("fun1(3.00)=%8.3lf",fun1(3.00));printf("fun1(3.76)=%8.3lf",fun1(3.76));}f(x

4、)=#include#includedoublef(floatx){/**//**/}voidmain(){floatx;doubley;printf("Pleaseinputanumber:");scanf("%f",&x);y=f(x);printf("f(%.3f)=%.3f",x,y);getch();}#include#includedoublef(floatx){/**//**/}voidmain(){floatx;doubley;printf("Pleaseinputanumber

5、:");scanf("%f",&x);y=f(x);printf("f(%0.2f)=%0.2f",x,y);getch();}