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1、AdvancedEnergySystemsHeatandMassTransferCoursework2013SubmittedBy:SubmittedTo:YuanGaoprofessorN.StosicStudentnumber:120048949MscmechanicalengineeringQuestion1:Givenissolidfuel:c=0.85,h=0.15,s=0.0,n=0.0,o=0.0.w=0.0,a=0.0a)DrawH-tdiagramandfindtheoreticaladiabatictempera
2、tureforexcessofaircoefficientoλ=1.25andairpreheattemperaturet=340C.oSolutiona):Fuelcomponentswhichburnarec,h.Thestochiometricequationoftheircompletecombustionare:C+O⇒CO122;H+O⇒HO2222Forc(kg/kg)ofcarbon:3312ckgC+22.4cNmO⇒22.4cNmCO22Fromwhichis:33ckg/kgC+1.867cNm/kgO⇒1.8
3、67cNm/kgCO22Forothercomponents:33hkg/kgH+5.6hNm/kgO⇒11.2hNm/kgHO222Thesestochiometricrelationsgiveaminimalquantityofoxygenneededforthecombustion:3v=1.867c+5.6h=1.867×0.85+5.6×0.15=2.427Nm/kgMinimalquantityofair:Vo22.4273V===11.557(Nm/kg)Lmin0.210.21Andaminimalquantityo
4、fdrycombustionproducts:3V=V+V=1.867c+0.79V=1.867×0.85+0.79×11.557=10.717(Nm/kg)RSminco2N2LminAminimalquantityofwetcombustionproducts:3V=V+V=V+11.2h=10.717+11.2×0.15=12.397(Nm/kg)RWminRSminH2ORSminAndrealquantityofairandcombustionproducts:V=λ⋅V=1.25×11.557=14.446LLminV=
5、V+(λ−1)V=10.717+(1.25−1)×11.557=13.606RSRSminLminV=V+(λ−1)V=12.397+(1.25−1)×11.557=15.286RWRWminLminH-tdiagramofthecombustionproductsgivearelationbetweenthetemperatureandenthaplywithanexcessofairasparameter.I=SVi=Vi+Vi+Vi+(λ−1)Viiico2CO2H2OH2ON2N2LminL3Where:V=1.867c,V
6、=11.2h,V=0.79V(Nm/kg)CO2H2ON2LminThiscalculationisprogrammedinFORTRAN,alistisgiventogetherwiththeinputandoutput2data,InputdataconsistofthepolinomialcoefficientsofspecificheatCp=a+bT+cTforCO,HO,N,inazduhinthe4rowsandonerowoffuelcomposition,resultsobtainedare222plottedin
7、theH-tdiagram.Hd=34,000×c+120,000×h=34,000×0.85+120,000×0.15=46,900KJ/KgoAirpreheattemperaturet=340C0WhenputHd=0kJ/kgintoprogram,wecanget:WhenputHd=46,900kJ/kgintoprogram,wecanget:FromovertwodiagramswecanknowthattheenthalpyofthecombustionproductsaresamevalueeitherHd=0k
8、J/kgorHd=46,900kJ/kg.ThenputallthevaluesintoEXCELsoftwaretoplotH-tdiagram,Accordingtotheresultsofprogram:3t=300℃=573.
