很不错的混凝土及钢筋混凝土工程实例识图及算量教程

《很不错的混凝土及钢筋混凝土工程实例识图及算量教程》由会员上传分享，免费在线阅读，更多相关内容在行业资料-天天文库。

1、混凝土及钢筋混凝土工程1.如图所示，求其中钢筋用量。【解】①(7.2-0.025×2+0.25×2)×4×1.58kg=48.35kg②(7.2-0.025×2＋0.25×2)×2×1.21kg=18.51kg③(7.2-0.025×2+0.25×2)×4×2.47kg＝75.58kg④(7.2-0.025×2+0.25×2)×2×0.888kg=13.59kg⑤(7.2-0.025×2)×2×0.888kg＝13.59kg⑥[(7.2-0.025×2)/0.2+1]×（0.2×2+0.65×2-8×0.03+2×

2、0.1）×0.395kg＝36.75×0.85×1.66×0.395kg=24.26kg⑦[(7.2-0.025×2)／0.2+1]×（0.35×2+0.2×2-8×0.03+2×0.077）×0.222kg=36.75×0.55×1.014×0.222kg=8.33kg2.如图所示，求现浇C25混凝土矩形梁钢筋用量。【解】①Φ22：[(6.3+0.12×2)-0.05+3.5×0.22×2]×2.98×2kg=47.86kg②Φ12：[(6.3+0.12×2)-0.05+3.5×0.12×2]×0.888×2kg

3、=13.02kg③Φ8：[(0.5+0.25)×2-0.15×8+0.16×2]×[(6.3+0.12×2)／0.2+1]×0.395kg=8.25kg④Φ22：[(6.3+0.12×2)-0.025×2＋2×0.414×(0.5-0.025×2)+2×(0.5-0.025×2)]×2.98×1kg=23.13kg⑤Φ22：[(6.3+0.12×2)-0.025×2+2×0.414×(0.5-0.025×2)+2×(0.5-0.025×2)]×2.98×1kg=23.13kg3.如图所示，求带型混凝土基础钢筋用量。

4、【解】①Φ20：[(29.7+0.6-0.035×2+0.2)×2+(13.2+0.6-0.035×2+0.2)×3+(9.9×2+0.6-0.035×2+0.2)+(6.6+0.6-0.035×2+0.2)]×4×2.47kg=130.51×4×2.47kg=1289.44kg②Φ18130.51×8×2kg=2088.16kg③Φ22[(29.7+0.6-0.035×2+0.2)×2+(13.2+0.6-0.035×2+0.2)×3+(9.9×2+0.6-0.035×2+0.2)+(6.6+0.6-0.035×

5、2+0.2)]×6×2.98kg=130.51×6×2.98kg=2333.52kg④Φ6130.51×[(1.8-0.035×2)／0.15+1]×0.395kg=646.1lkg⑤Φ8(1.8-0.035×2+6.25×0.006×2)×(130.51／0.15+1)×0.222kg=349.02kg4.如图所示，求楼梯中钢筋用量。【解】(0.6+0.2)×[(3.6／2-0.015×2)／0.12+1]×0.888kg＝11.19kg(1.77+0.1)×[(0.6×2+2.7×1.15×2+0.6+0.8)

6、／0.18+1]×0.395kg=1.87×50×0.395kg=36.93kg(0.2+0.6+0.2)×[(3.6／2-0.015×2)／0.12+1]×0.888kg＝13.99kg(3.0+0.06+1.185+0.06)×15×0.888×2kg＝114.69kg(3.57+0.1)×14×0.617kg＝31.7kg(0.9+0.2+0.1+0.05)×15×0.617kg＝11.57kg(0.4+0.4+0.14)×15×0.888kg＝12.52kg(0.4+0.7×2)×(3.6／0.2+1)×2

7、×0.395kg＝27.018kg(0.040×2+3.57)×14×0.395kg＝20.1845kg2.44×19×0.26kg＝12.06kg附加钢筋：由于XB-2在XB-1中，只配了上部筋，无下部筋，故应加：由于XB3在XB-1中，只配了下部筋，无上部筋，故应加：17根所以,应加配：Φ10：(0.06×2+1.185)×34×0.617kg＝27.38kg5.如图所示，共100个柱，求基础工程量及综合基价。【解】基础工程量＝60×45×0.2+(60-0.25×2)×(45-0.25×2)×0.3+｛0.8

8、×0.8×0.4+[0.8×0.8+(0.8+0.6)×(0.8+0.6)+0.6×0.6]×0.35÷6｝×l00m3＝1377.19m3执行5－9子目，综合基价为：137.719×4611.09元/10m3=635034.70元6.如图所示，求满堂有梁基础工程量及综合基价。【解】满堂有梁基础工程量＝20×12.8×0.3+0.3×0.45×(20×3+1