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1、实用标准文案本例题的主要部分为一个圆筒形罐，其上沿径向有一材料一样的接管（如图？？？？所所示），罐内流动着450°F（232°C）的高温流体，接管内流动着100°F（38°C）的低温流体，两个流体区域由薄壁管隔离。罐的对流换热系数为250Btu/hr-ft2-oF（1420watts/m2-°K），接管的对流换热系数随管壁温度而变，它的热物理性能如表？？？所示。要求计算罐与接管的温度分布。表？？？？温度70200300400500oF密度0.2850.2850.2850.2850.285lb/in3导热系数8.358.909.359.810.23Bt
2、u/hr-ft-oF比热0.1130.1170.1190.1220.125Btu/lb-oF对流换热系数426405352275221Btu/hr-ft2-oF6.5.1预处理Step1:确定分析标题起动ANSYS后，开始一个分析，需要输入一个标题，按下面方法进行操作：1.选择Utility Menu>File>ChangeTitle，弹出相应对话框2.输入 Steady-statethermalanalysisofpipejunction。3.点击OK。Step2:设置分析单位系统文档大全实用标准文案Youneedtospecifyunitsofm
3、easurementfortheanalysis.Forthispipejunctionexample,measurementsusetheU.S.Customarysystemofunits(basedoninches).Tospecifythis,typethecommand /UNITS,BINintheANSYSInputwindowandpressENTER.在分析之前，需要为分析系统设定单位系统，Step3:DefinetheElementTypeTheexampleanalysisusesathermalsolidelement.Tod
4、efineit,dothefollowing:1.Choose Main Menu>Preprocessor>ElementType>Add/Edit/Delete.TheElementTypesdialogboxappears.2.ClickonAdd.TheLibraryofElementTypesdialogboxappears.3.Inthelistontheleft,scrolldownandpick(highlight)"ThermalSolid."Inthelistontheright,pick"Brick20node90."4.Cli
5、ckonOK.5.ClickonClosetoclosetheElementTypesdialogbox.Step4:DefineMaterialPropertiesTodefinematerialpropertiesfortheanalysis,performthesesteps:1.Choose Main Menu>Preprocessor>MaterialProps>MaterialModels.TheDefineMaterialModelBehaviordialogboxappears.2.IntheMaterialModelsAvailab
6、lewindow,double-clickonthefollowingoptions:Thermal,Density.Adialogboxappears.3.Enter.285forDENS(Density),andclickonOK.MaterialModelNumber1appearsintheMaterialModelsDefinedwindowontheleft.4.IntheMaterialModelsAvailablewindow,double-clickonthefollowingoptions:Conductivity,Isotrop
7、ic.Adialogboxappears.5.ClickontheAddTemperaturebuttonfourtimes.Fourcolumnsareadded.6.IntheT1throughT5fields,enterthefollowingtemperaturevalues:70,200,300,400,and500.Selecttherowoftemperaturesbydraggingthecursoracrossthetextfields.ThencopythetemperaturesbypressingCtrl-c.7.IntheK
8、XX(ThermalConductivity)fields,enterthefollowingvalues,
