上机考试的试卷

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1、/*------------------------------------------------【程序设计】--------------------------------------------------功能：计算出k以内最大的10个能被13或17整除的自然数之和。（k〈3000）。------------------------------------------------*/#include#include"conio.h"voidbky();intfun(intk){/****

2、******Begin**********/inti;longsum;for(i=0,sum=0;i<10;){if(!(k%13)

3、

4、!(k%17)){sum+=k;++i;}--k;}returnsum;/**********End**********/}main(){intm;printf("Enterm:");scanf("%d",&m);printf("Theresultis%d",fun(m));bky();}voidbky(){FILE*IN,*OUT;ints;intt;into;IN=

5、fopen("in.dat","r");if(IN==NULL){printf("ReadFILEError");}OUT=fopen("out.dat","w");if(OUT==NULL){printf("WriteFILEError");}for(s=1;s<=5;s++){fscanf(IN,"%d",&t);o=fun(t);fprintf(OUT,"%d",o);}fclose(IN);fclose(OUT);填空1.以下程序的功能是计算请填空。longf(intn){inti;longs;s=

6、__1___;for(i=1;i<=n;i++)s=__s*i___;returns;}main(){longs;intk,n;scanf("%d",&n);s=__0___;for(k=0;k<=n;k++)s=s+__f(k)___;printf("%d",s);}2.以下程序的输出结果是__2,5,1,3,3,-2___。main(){inta=3,b=2,c=1;c-=++b;b*=a+c;{intb=5,c=12;c/=b*2;a-=c;printf("%d,%d,%d,",a,b,c);a+=-

7、-c;}printf("%d,%d,%d",a,b,c);}3.以下程序的输出结果是_4____。fun1(inta,intb){intc;a+=a;b+=b;c=fun2(a,b);returnc*c;}fun2(inta,intb){intc;c=a*b%3;returnc;}main(){intx=11,y=19;printf("%d",fun1(x,y));}4.以下程序的输出结果是__15.500000___。doublesub(doublex,doubley,doublez){y-=1.0;

8、z=z+x;returnz;}main(){doublea=2.5,b=9.0;printf("%f",sub(b-a,a,b));}5.下面pi函数的功能是，根据以下公式返回满足精度eps要求的π的值。请填空。doublepi(doubleeps){doubles=0.0,t=1.0;intn;for(__s=0,t=1,n=1___;t>eps);n++){s+=t;t=n*t/(2*n+1);}return(2.0*_s____);}程序改错/*----------------------------

9、--------------------------【程序改错】--------------------------------------------------------功能：根据以下公式求π值，并作为函数值返回。例如：给指定精度的变量eps输入0.0005时，应当输出Pi=3.140578。π1121231234-=1+-+-x-+-x-x-+-x-x-x-+...23353573579------------------------------------------------------*/#in

10、cludedoublefun(doubleeps){doubles,t;intn=1;s=0.0;t=1;/**********ERROR**********/while(t>=eps){s+=t;/**********ERROR**********/t=t*n/(2*n+1);n++;}/**********ERROR**********/return2.0*s;}