C++第4次作业

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1、1.设计并测试一个名为Rectangle的矩形类，其属性为矩形的左上角与右下角两个点的坐标，根据坐标能计算矩形的面积。（1）实验目的：根据坐标求矩形的面积。（2）实验分析：类的基础题，题目的主要难点在于函数的调用。（3）程序代码：#includeusingnamespacestd;classRectangle{public:Rectangle(doublenewL1=0,doublenewL2=0,doublenewR1=0,doublenewR2=0);doubleGetArea()const

2、;private:doubleleft1,left2,right1,right2;};Rectangle::Rectangle(doublenewL1,doublenewL2,doublenewR1,doublenewR2){left1=newL1;left2=newL2;right1=newR1;right2=newR2;}doubleRectangle::GetArea()const{doubleWidth=right1-left1;doubleHeight=right2-left2;return(Width*

3、Height);}intmain(){RectangleMyRectangle(10,20,50,80);doubleArea=MyRectangle.GetArea();cout<<"矩形的面积:"<#defineP

4、i3.14usingnamespacestd;classCircle{private:doubleRadius;public:Circle(doubleR){Radius=R;}doubleGetArea();};doubleCircle::GetArea(){returnPi*Radius*Radius;}voidmain(){doublei;cout<<"请输入半径:"<>i;CircleC(i);doublearea=C.GetArea();cout<<"面积为:"<

5、;}（3）运行结果:2.设计一个类sample,实现两个复数的加法和减法运算。(1)实验分析：题目不难，将复数的实部和虚部分开加减即可(2)程序代码：#includeclassSample{private:doublereal;doubleimag;public:Sample(doubler=0.0,doublei=0.0);voidprint();SampleSample::operator+(Samples);SampleSample::operator-(Samplem);};Samp

6、le::Sample(doubler,doublei){real=r;imag=i;}SampleSample::operator+(Samples){Samplea;a.real=real+s.real;a.imag=imag+s.imag;returna;}SampleSample::operator-(Samplem){Samplea;a.real=real-m.real;a.imag=imag-m.imag;returna;}voidSample::print(){cout<0)

7、cout<<"+";if(imag!=0)cout<>r1>>i1;cout<<"请输入第二个复数的实部和虚部:"<>r2>>i2;Samples1=Sample(r1,i1),s2=Sample(r2,i2);Samples3=s1+s2;cout<<"两复数的和为:";s3.print();cout<

8、1,i1),m2=Sample(r2,i2);Samplem3=m1-m2;cout<<"两复数的差为:";m3.print();cout<