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ID:35275187
大小:23.48 KB
页数:28页
时间:2019-03-22
《C语言操作题常考编程题库》由会员上传分享,免费在线阅读,更多相关内容在教育资源-天天文库。
1、C语言编程题覆盖到的算法:1、个人所得税计算;2、求一组数的正、负数(或奇、偶数)的个数和平均值;3、二维数组主、次对角线之和;4、求素数(用函数实现);5、级数有限项求和问题;6、两个一维数组相加(用函数实现);7、求最大、最小值;8、判断闰年(用函数实现);9、求水仙花数;10、百钱百鸡;11、求最大公约数、最小公倍数。12、求回文数;13、排序;14、二维数组的转置;15、递归函数求阶乘;16、求斐波那契数列;17、求和:a+aa+aaa+aaaa+....;18、求符合条件的整数(如:是某个二位数的平方,个位、十位、百位数各不相同等);(包括素数,回
2、文,完数,等等)19、字符串加密;20、统计字符串中字母和数字的个数;/*1.个人所得税计算,以实验指导P24T5为标准*/#includevoidmain(){inti,n;doublea,b,c;n=i/400;printf("pleaseinputincome:");scanf("%d",&i);a=(i-800)*0.05,b=20+(i-1200)*0.08,c=84+(i-2000)*0.2;switch(n){case0:case1:printf("不需缴税");break;case2:printf("需交纳%lf元
3、n",a);break;case3:case4:printf("需交纳%lf元",b);break;default:printf("需交纳%lf元",c);break;}}/*2.求一组数的奇数个数,偶数个数和平均值#include#defineN10voidmain(){inta[N];inti,m=0,n=0,sum=0;doubleaverage;printf("pleaseinput10numbers:");for(i=0;i4、++;sum+=a[i];}average=(double)sum/N;printf("wehave%doddsand%devens",n,m);printf("average=%lf",average);}*//*2'.求一组数的正数个数和负数个数与平均值*/#include#defineN10voidmain(){inta[N];inti,m=0,n=0,sum=0;doubleaverage;printf("pleaseinput10numbers:");for(i=0;i5、;if(a[i]>0)m++;elsen++;sum+=a[i];}average=(double)sum/N;printf("wehave%dpositivenumbersand%dnagetivenumbers",m,n);printf("theaverage=%lf",average);}/*3.求二维数组的主次对角线之和*/#include#defineM5#defineN5voidmain(){inta[M][N];inti,j,sum1=0,sum2=0;printf("pleaseinputthematrix:");f6、or(i=0;i#includeintisPrime(intn){inti;for(i=1;i7、{if(n%i==0)return0;}return1;}voidmain(){intn,i;printf("pleaseinputanumber");scanf("%d",&n);i=isPrime(n);if(i)printf("%disaprime",n);elseprintf("%disnotaprime",n);}//5.级数有限项求和(以格里高利公式求π为例)//#include#includevoidmain(){intn=1;doublep=0,t,pi;t=1/(pow((-1),(n+1))*8、2*(n-1));while(fabs(t)>=1e
4、++;sum+=a[i];}average=(double)sum/N;printf("wehave%doddsand%devens",n,m);printf("average=%lf",average);}*//*2'.求一组数的正数个数和负数个数与平均值*/#include#defineN10voidmain(){inta[N];inti,m=0,n=0,sum=0;doubleaverage;printf("pleaseinput10numbers:");for(i=0;i5、;if(a[i]>0)m++;elsen++;sum+=a[i];}average=(double)sum/N;printf("wehave%dpositivenumbersand%dnagetivenumbers",m,n);printf("theaverage=%lf",average);}/*3.求二维数组的主次对角线之和*/#include#defineM5#defineN5voidmain(){inta[M][N];inti,j,sum1=0,sum2=0;printf("pleaseinputthematrix:");f6、or(i=0;i#includeintisPrime(intn){inti;for(i=1;i7、{if(n%i==0)return0;}return1;}voidmain(){intn,i;printf("pleaseinputanumber");scanf("%d",&n);i=isPrime(n);if(i)printf("%disaprime",n);elseprintf("%disnotaprime",n);}//5.级数有限项求和(以格里高利公式求π为例)//#include#includevoidmain(){intn=1;doublep=0,t,pi;t=1/(pow((-1),(n+1))*8、2*(n-1));while(fabs(t)>=1e
5、;if(a[i]>0)m++;elsen++;sum+=a[i];}average=(double)sum/N;printf("wehave%dpositivenumbersand%dnagetivenumbers",m,n);printf("theaverage=%lf",average);}/*3.求二维数组的主次对角线之和*/#include#defineM5#defineN5voidmain(){inta[M][N];inti,j,sum1=0,sum2=0;printf("pleaseinputthematrix:");f
6、or(i=0;i#includeintisPrime(intn){inti;for(i=1;i7、{if(n%i==0)return0;}return1;}voidmain(){intn,i;printf("pleaseinputanumber");scanf("%d",&n);i=isPrime(n);if(i)printf("%disaprime",n);elseprintf("%disnotaprime",n);}//5.级数有限项求和(以格里高利公式求π为例)//#include#includevoidmain(){intn=1;doublep=0,t,pi;t=1/(pow((-1),(n+1))*8、2*(n-1));while(fabs(t)>=1e
7、{if(n%i==0)return0;}return1;}voidmain(){intn,i;printf("pleaseinputanumber");scanf("%d",&n);i=isPrime(n);if(i)printf("%disaprime",n);elseprintf("%disnotaprime",n);}//5.级数有限项求和(以格里高利公式求π为例)//#include#includevoidmain(){intn=1;doublep=0,t,pi;t=1/(pow((-1),(n+1))*
8、2*(n-1));while(fabs(t)>=1e
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