信号处理导论(英文影印版) 课后习题答案_1-6章new

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1、第一章1.1f=61)f=8Hzf=fmod(f)=−2sastheobserverperceivethewrongsenseofrotation2)f=12Hzf=fmod(f)=±6saswww.khdaw.comtheobserverlosethesenseofrotation3)f=16Hzf=fmod(f)=6sastheobserverperceivethecorrectsenseofrotation课后答案网4)f=24Hzf=fmod(f)=6sastheobserverperceivethecorrectsenseofrotation课后答案网www.khdaw.c

2、om1.2f=1Hz,f=4Hz,f=6Hz1231)f=5HzNyquistinterval:[−2.5,2.5]sf=fmod(f)=1mod(5)=1;1a1sf=fmod(f)=4mod(5)=−1;2a2sf=fmod(f)=6mod(5)=www.khdaw.com1;3a3sx(t)=10sin(2πft)+10sin(2πft)+5sin(2πft)=5sin(2πt)a1a2a3ax(nT)=5sin(2πnT)=5sin(2πn/f)=5sin(2πn/5)asx(nT)=10sin(2πn课后答案网/5)+10sin(8πn/5)+5sin(12πn/5)=5s

3、in(2πn/5)∴x(nT)=x(nT)a课后答案网www.khdaw.com2)f=10HzNyquistinterval:[−5,5]sf=fmod(f)=1mod(10)=1;1a1sf=fmod(f)=4mod(10)=4;2a2sf=fmod(f)=6mod(10)=−4;3a3sx(t)=10sin(2πft)+10sin(2πft)+5sin(2πft)a1a2a3awww.khdaw.com=10sin(2πt)+5sin(8πt)x(nT)=10sin(2π/10)+5sin(8π/10)ax(nT)=10sin(2πn/10)+10sin(8πn/10)+5si

4、n(12πn/10)课后答案网=10sin(2π/10)+5sin(8π/10)∴x(nT)=x(nT)a课后答案网www.khdaw.com1.3x(t)=2cos(πt)−cos(5πt)f=05kHz,f=2.5kHz12f=3kHzNyquistinterval:[−2.5k,2.5k]s1)www.khdaw.comf=fmod(f)=0.5mod(3)=0.5;1a1sf=fmod(f)=2.5mod(3)=−0.5;2a2sx(t)=2cos(2πft)−cos(2πft)=cos(πt)a1a2a课后答案网2)x(t)=2cos[2π(f+mf)t]−cos[2π(f

5、+mf)t]mn1s2s课后答案网www.khdaw.com1.9a)f=5kHz,f=10kHz,f=30kHz,f=45kHz1234f=40kHzNyquistinterval:[−20k,20k]sf=fmod(f)=5k;f=fmod(f)=10k;1a1s2a2swww.khdaw.comf=fmod(f)=−10k;f=fmod(f)=5k;3a3s4a4sy(t)=2sin(10πt)ab)课后答案网theoutputoftheprefilter:y(t)=sin(10πt)+sin(20πt)y(t)=y(t)a课后答案网www.khdaw.comc)通过prefi

6、lter后信号在频率f处的幅度值：330−28.078/2048log()=28.078dB⇒H(f)=10=0.03952320通过prefilter后信号在频率f处的幅度值：445−56.156/2048log()=56.156dB⇒H(f)=10=0.00162420∴theoutputoftheprefilterwww.khdaw.comis:y(t)=sin(10πt)+sin(20πt)+0.0395sin(60πt)+0.0016sin(90πt)f=fmod(f)=5k;f=fmod(f)=10k;1a1s2a2sf=fmod(f)=−10k;f=fmod(f)=5k

7、;3a3s课后答案网4a4s∴theoutputoftheanalogreconstructoris:y(t)=sin(10πt)+sin(20πt)+0.0395(−20πt)+0.0016sin(10πt)a=1.0016sin(10πt)+0.9605sin(20πt)课后答案网www.khdaw.com第二章2.1R16Q===2B3221)x=3.7;truncation;two’scomplementbipolarADCtestb1b2b3mw