电路分析基础(英文版)课后答案第二章

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1、2SomeCircuitSimpli¯cationTechniquesDrillExercisesDE2.116k64=12:8−;12:8+7:2=20−;20k30=12−[a]v=5(12)=60V[b]p5A(del)=(5)(60)=300W[c]iA=60=30=2AiC=3(64)=(80)=2:4Ai=5¡2=3Ap=(2:4)210=57:6WB10−DE2.2[a]vo(noload)=200(75)=100=150V[b]75k150=50k−,thereforevo=200(50)=75=133:3V[c]i=200=

2、25;000=8mA,p=(8£10¡3)2(25;000)=1:6W25k[d]Maximumdissipationatnoloadsincevoismaximumv2op==0:3W75;0002728CHAPTER2.SomeCircuitSimpli¯cationTechniquesDE2.3v30v30=6+4(0:825)=9:3V;i30==0:31A30i6=i30+0:825=1:135A;i10=0:825+0:31=1:135A¡v30¡6ib+v20¡10i10=0::v¢20=9:3+16(1:135)=27:46V

3、27:46i20==1:373A;i5=i6+i20=2:508A20i30=0:31A;i6=1:135A;i10=1:135A;i20=1:373A;andi5=2:508ADE2.4Problems2972i==6A1272120¡57:6[a]v=(8)=48V;i120V==3:12A1220[b]va=6(9:6)=57:6V;p120V(del)=120ia=374:40WDE2.5[a]110Vsourceactingalone:10(14)35Re==−2460110132i==A5+35=613µ¶µ¶035132770v

4、o==V613134Asourceactingalone:5−k10−=50=15=10=3−10=3+2=16=3−30CHAPTER2.SomeCircuitSimpli¯cationTechniques16=3k12=48=13−Henceourcircuitreducesto:Itfollowsthat00va=4(48=13)=(192=13)Vand¡v00500a00vo=(10=3)=¡va=¡(120=13)V(16=3)8::¢v=v0+v00=770¡120=50Vooo1313v2o[b]p==250W10DE2.67

5、0-Vsourceactingalone:00v=70¡4ibv0v00b00is=+=ia+ib2100070=20ia+vb70¡v00bia=20Problems31v0v070¡v011v0::¢i0=b+¡b=v0+¡3:5bb210202010000v=vb+2ib::v¢0=v0¡2i0bb11v01370::i¢0=(v0¡2i0)+¡3:5ori0=v0¡bbb20104242µ¶::v¢0=70¡413v0¡70orv0=3220=1610V4242944750-Vsourceactingalone:0000v=¡4ib0

6、00000v=vb+2ib0000v=¡50+10idv00+50::i¢00=d10v00v00+5000bis=+210v00v00v00v00+5011v00+5000b00bb00ib=+is=++=vb+20202102010000000vb=v¡2ib11v00+5013100::i¢00=(v00¡2i00)+ori00=v00+bbb20104242µ¶00130010000200Thus,v=¡4v+orv=¡V42424700016102001410Hence,v=v+v=¡==30V47474732CHAPTER2.So

7、meCircuitSimpli¯cationTechniquesProblemsP2.1[a]p=i24=(12)24=576Wp=(4)218=288W4−s18−p=(8)23=192Wp=(8)26=384W3−6−[b]p120V(delivered)=120is=120(12)=1440W[c]pdiss=576+288+192+384=1440WP2.2[a]FromEx.3-1:i1=4A,i2=8A,is=12Aatnodex:¡12+4+8=0,atnodey:12¡4¡8=0[b]v1=4is=48Vv3=3i2=24Vv

8、2=18i1=72Vv4=6i2=48Vloopabda:¡120+48+72=0;loopbcdb:¡72+24+48=0;loopabcda:¡120+48+2