用c语言编写万年历

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1、#include//假设今天是2013年12月22号，是星期天，根据这个日期计算日历中的某天距离今天有多少天，且输入的日期为星期几！查表得1800年1月1日为星期三。inti,j,k,a,b,c,w=0;//i,j,k分别代表全局变量的年月日。inty(){intp,h=0,inleap=0,leap=0,sum=0,count1,count2,leap1;scanf("%d",&i);if(i>2100

2、

3、i<1800)printf("输入的年份不合法，或者不在程序运算的范围内");else{printf("%d年的年历为：",i);for(j=1;j<=12;

4、j++){{for(a=1800;a<=i;a++){if((a%4==0&&a%100!=0)

5、

6、(a%400==0))leap++;elseinleap++;}count1=leap*366;count2=inleap*365;switch(j){case1:sum=0;break;case2:sum=31;break;case3:sum=59;break;case4:sum=90;break;case5:sum=120;break;case6:sum=151;break;case7:sum=181;break;case8:sum=212;break;case9:sum=243;b

7、reak;case10:sum=273;break;case11:sum=304;break;case12:sum=334;break;}sum=sum+count1+count2;{if(i%400==0

8、

9、(i%4==0&&i%100!=0))leap1=1;//如果不是闰年则直接执行elseleap1=0;if(leap1==1&&j>2)//如果是闰年并且月份大于2,总天数应该加一天sum++;}h=(sum+2)%7;}if((i%4==0&&i%100!=0)

10、

11、(i%400==0)){switch(j){case1:case3:case5:case7:case8:case

12、10:case12:printf("tt%d月",j);printf("%4s%4s%4s%4s%4s%4s%4s","Sun","Mon","Tues","Wed","Thur","Fri","Sat");for(p=0;p

13、n","Sun","Mon","Tues","Wed","Thur","Fri","Sat");for(p=0;p

14、);if((c+h)%7==0)printf("");}printf("");}}else{switch(j){case1:case3:case5:case7:case8:case10:case12:printf("tt%d月",j);printf("%4s%4s%4s%4s%4s%4s%4s","Sun","Mon","Tues","Wed","Thur","Fri","Sat");for(p=0;p

15、intf("");break;case4:case6:case9:case11:printf("tt%d月",j);printf("%4s%4s%4s%4s%4s%4s%4s","Sun","Mon","Tues","Wed","Thur","Fri","Sat");for(p=0;p