工程地质与地基基础作业答案

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1、i心止鸣f9眇0-£州00LLd9S90_l-Ix（860*0+1）X£97_1-”〃（M+l）Z>-3z-s9-20+1勺+1久严加壮"久卡"<=齐厂刁鸳8代=/<=严8R0=XV%0+1刀+1“7H£^8fyO=———xix6-0=——AcS=cASo0c,560+1刀+1pIMf^8ro=———xlx厶£Q=h/Vs=ASo0a(5/沁十u(5W爪^/NW6=ss-s£-2SA严。9厶9°0=X-人=X'严》乙£P=卞=X干吐國*力乙£0=W=Mtu余乙9,1=*/4仅=沁=人：令%0乙二皿'严/2汽°91=仅严/M69匸哈叹严/M901=欣-叹=^d-S^iu=&£/

2、M7UCUL[X厶乙+门乙I9人+巾凹丨N列6L=A沁=人，%Q9=加厂巾=m严厶乙=X-人=aamA=Lm="di'iu=X%L=S-U!=%:fijjf呂门乙［=切(3'6U=^乙厶=人彩口3-1解:£2/(1+也十2.73><(]+0.31)><

3、亠08821.925.5Ysatlq+j_2.73+0.882x]0=]92如加31+0.8821+e7wq=G、(l+w)几i2.74x(l+0.41)xli3P'1.83f产-yw='74+Llll%io=18.2RN/m3Sl+£"1+1.111匂/(1+忙+2.72x(1+0.27)x1+0771P1.95sat4^±

4、£人=2.72+0.771x]0=]97rn/加3l+ew1+0.771V3567.2132.8161.93-2解:Pk=人2=—+/Gd=便+20x2=125"°AA4x2e=680x1.31=o.89O8qJ6Fk+Gk680+20x4x2x2634-3Pkmax=2(以+GJ=2x(680+20x4x2x2)=3bk3x2x(2-0.8908)解:a]f=a.tan2(45°+/2)+2ctan(45°+(p/2)=435.2kPa4-4解:a]f=a3tan2(45°+2)+2ctan(45°+(p/2)=210xtan2(45。+25。/2)+2x36xtan(45°+

5、25°/2)=630AkPa>q或者切“卫讥45~/2)-2ctan(45~/2),弹性状态，安全=380xtan2(45°-25°/2)-2x36xtan(45°一25°/2)=108.4kPac=47.3kPa0=30。解:PaA-2cy[K^=-2x20xtan(45°-18°/2)=—29.06"aPaB-2Cy[K^=tan2(45°-18°/2)xl8x5-2x20xtan(45°-18°/2)=1SAkPaP：b=KM严tan2(45°-35°/2)xl8x

6、5=24AkPapaC=A；?("/?]+/2/?2)=tan*2(45。—35。/2)x(18x5+20x3)=40.6kPaEa=-xl8.4x(5-3.07)+-x(24.4+40.6)x3=115.3^22i5_307]/?(Z=[-xl&4x(5-3.07)x(3+—)+-x24.4x3x2+

7、x40.6x3xl]/115.3=1.73m7-3解：fa=fak+n(iYm(^-0.5)=185+1.6x18.6x(1.1-0.5)=202.9kPa殆_L=_180—十fa-yGd202.9-20x1.17-4解：fa=£火+〃必"-0.5)=210+1x18x(1.9-

8、0.5)=235.2"°2400人-12fa~Ycd=12X235.2-20x1.9二"皿//b=1.5=>/?=yJA/n=3.2m,I=nb=4.8//?850+60x1.4解:M850+60x1.4八…4e===0.313m<—mF+G2400+20x4.8x3.2x1.96F+G"6幺、2400+20x4.8x3.2x1.9Z16x0.313、“c“门wn仇=(1+—)=x(l+)=270.3"。<1.2/,=282.2kPaAmaxA/4.8x3.24.8a故取/=4.8加，b=3.2m4.8x3.2fa=fak+a几(d-0.5)=184+1.1x15.7x(1.35

9、-0.5)=19&IkPa取正方形基础，叫急下卧层验算：F7X0/?0=—4-yGd-ymd-——+20x1.5-15.7x1.35=H0kPaA2.2170x2.22Es]/Es2=5,zlb=m6~(b+2ztan0)2-(2.2+2x2xtan25°)-49'SkPa=15.7x135+1&6x2=58.4"。584九二氏+〃仇(d-0.5)=88+l.lx莎x(3.35-0.5)=142.7"。6+兀=49.8+58.4=108.2"d<£「满足7-7解：持力层验算：“