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1、11.6-1WellboreHydraulics,PressureDropCalculations21.6-2WellboreHydraulicsHydrostaticsBuoyancyPipeTensionvs.DepthEffectofMudPressureLaminarandTurbulentFlowPressureDropCalculationsBinghamPlasticModelAPIPower-LawModel31.6-3BuoyancyForce=weightoffluiddisplaced(Archimedes,250
2、BC)Figure4-9.Hydraulicforcesactingonasubmergedbody41.6-4Effective(buoyed)WeightBuoyancyFactorValidforasolidbodyoranopen-endedpipe!We=buoyedweightW=weightinairFb=buoyancyforceV=volumeofbodyrf=fluiddensityrs=bodydensity51.6-5AxialForcesinDrillstringFb=bitweightF1&F1arepres
3、sureforces61.6-6AxialTensioninDrillStringExampleAdrillstringconsistsof10,000ftof19.5#/ftdrillpipeand600ftof147#/ftdrillcollarssuspendedoffbottomin15#/galmud(Fb=bitweight=0).Whatistheaxialtensioninthedrillstringasafunctionofdepth?71.6-7ExamplePressureattopofcollars=0.052(
4、15)10,000=7,800psiPressureatbottomofcollars=0.052(15)10,600=8,268psiCross-sectionalareaofpipe,A110,000’10,600’8Cross-sectionalareaofcollars,A2A11.6-8Example–cont’d91.At10,600ft.(bottomofdrillcollars)Compressiveforce=pA=357,200lbf[axialtension=-357,200lbf]43211.6-9Example
5、-cont’d101.6-10Example-cont’d2.At10,000ft+(topofcollars)FT=W2-F2-Fb=147lbm/ft*600ft-357,200=88,200-357,200=-269,000lbf4321Fb=FBIT=0113.At10,000ft-(bottomofdrillpipe)FT=W1+W2+F1-F2-Fb=88,200+7800lbf/in2*37.5in2-357,200=88,200+292,500-357,200=+23,500lbf43211.6-11Example-co
6、nt’d124.AtSurfaceFT=W1+W2+F1-F2-Fb=19.5*10,000+88,200+292,500-357,200-0=218,500lbfAlternatively:FT=WAIR*BF=283,200*0.7710=218,345lbf43211.6-12Example-cont’d13Fig.4-11.AxialtensionsasafunctionofdepthforExample4.91.6-13141.6-14AxialLoadwithFBIT=68,000lbf
