基于忙音的ad+hoc网络mac协议-研究

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1、ResearchonBusyTonebasedMACProtocolinAdhocNetworkAbstractAdhocnetwork，alsoknownasMANET'isakindofnetworkwhichconsistsofasetofnodeswithwirelessdevicefortransmittingandreceivingandcanbequicklysetup．Asithasthefeaturessuchasmulti-hop，dynamicnetworktopology,distributedco

2、ntrol，anddoesnotrelyonbasestations，ithasabroadapplicationprospectandhasbeensubjecttoacademicandindustrialattention．MediaaccesscontrolprotocoliSusedtocoordinatenodestoaccessthesharedchannelandreducesconflicts，SOitisakeytechnologytoadhocnetwork．ExistingMACprotocolsl

3、ikeIEEE802．11iswidelyusedinadhoenetwork，however,802．11willbringabouttheunfaimessofchannelaccess，hiddenterminalandexposedterminalproblems．Manystudieshavetriedtoimprovetheperformanceofadhocnetwork，whereas，theseMACprotocolsusuallyconsideronlyanidealnetworkenvironment

4、，namely,thetosendpacketsobtaintransmitter-receiver’Sid，thenevaluatewhethertheyarewithinthereceiver’Sinterferencerange，thusdeterminewhethersendpacketsornot．Analysisandsimulationshowthat，theproposedprotocolcanpreventthehiddenterminalinthelargeinterferenceareaandalso

5、alleviatetheexposedterminalproblem．Finally,wemakeananalysisoftheinterferenceaccumulationphenomenoninadhocnetworkandproposeaHexagonmodelbasedMACprotoc01．Theprotocoladjuststhetransmissionpowerofreceiver’Sbusytoneaccordingconflictsofdatapacket．Whenreceiverfailsreceiv

6、edatapacket，itwillenhancethebusytonetransmissionpowerenlargeinterferencecontrolradius，SOasreceivedatapacketsuccessfully．Analysisandsimulationshowthat，theprotocolcanimprovetheprobabilityofthereceiverreceivepacketcorrectlyinthecaseofmultipleinterferencesource，andbet

7、teralleviatethehiddenterminalprobleminthelargeinterferencearea．Keywords：Adhocnetwork；Backoffalgorithm；MAC；Busytone；LargeinterferenceareaIliWrittenbyHeShuangshengSupervisedbyZhangGuangquan目录第一章绪论⋯⋯⋯⋯⋯⋯⋯⋯⋯⋯⋯⋯⋯⋯⋯⋯⋯⋯⋯⋯⋯⋯⋯⋯⋯⋯⋯⋯⋯⋯．11．1研究背景与意义⋯⋯⋯⋯⋯⋯⋯⋯⋯⋯⋯⋯⋯⋯⋯⋯⋯⋯⋯⋯⋯⋯⋯⋯⋯。l1

8、．2本文研究内容⋯⋯⋯⋯⋯⋯⋯⋯⋯⋯⋯⋯⋯⋯⋯⋯⋯⋯⋯⋯⋯⋯⋯⋯⋯⋯．．21．3本文组织结构⋯⋯⋯⋯⋯⋯⋯⋯⋯⋯⋯⋯⋯⋯⋯⋯⋯⋯⋯⋯⋯⋯⋯⋯⋯⋯．3第二章Adhoc网络MAC协议⋯⋯⋯⋯⋯⋯⋯⋯⋯⋯⋯⋯⋯⋯⋯⋯⋯⋯⋯⋯⋯⋯．．42．1MAC协议分类⋯⋯⋯⋯⋯⋯⋯⋯⋯⋯⋯⋯⋯⋯⋯⋯⋯⋯⋯⋯⋯⋯⋯⋯⋯⋯42