sparc、mmp2在大肠癌组织的表达其临床意义

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1、华中科技大学硕士学位论文结论：SPARC在大肠癌组织中低表达，而MMP-2在大肠癌组织中高表达表达，提示两者在大肠肿瘤的发展、浸润、转移过程中发挥重要作用，并可能为大肠癌早期诊断筛查及预后提供新思路。关键词：SPARC；MMP-2；大肠癌；大肠腺瘤；免疫组织化学；间质细胞3万方数据华中科技大学硕士学位论文TheexpressionofSPARC&MMP-2andclinicalsignificanceinhumancolorectalcarcinomaPostgraduate：WuJieSupervisor：Prof.CaoShiqiongABSTRACTOb

2、jective:ToinvestigatetheexpressionandclinicalsignificanceofSPARC(Secretedproteinacidicandrichincysteine)andMMP-2(MatrixMetalloproteinase-2)inhumancolorectalcarcinomaandcolorectaladenoma.TodiscussthepossiblemechanismandtherelationshipofSPARCandMMP-2inthedevelopmentandtheprogressionof

3、colorectaltumour.Methods:UsingtheimmunohistochemicaltechniquetoinvestigatetheexpressionofSPARCandMMP-2in65casescolorectalcarcinoma、32casescolorectaladenomaand29casesnormalcolorectaltissues.Results:○1ImmunohistochemicalresultsshowthattheexpressionofSPARCweredifferentinlargeintestinal

4、cancercellsandstromalcells.Comparedwithcoloncarcinomia,colorectaladenomaandnormalcolorectaltissue,thepositiveexpressionratesofSPARCintheglandcellshavenosignificantdifferences(P>0.05),whilethedifferencewasclearinstromalcells（P<0.05）.○2TheexpressionofSPARCincolorectalcancerstromalcell

5、shassignificantcorrelationwiththedegreeofdifferentiationanddegreeoflymphaticmetastasis,butthereisnocorrelationinpatientfactorssuchasage,genderandthepartofthetumor.○3ImmunohistochemicalresultsshowthattheexpressionsofMMP-2weredifferentinlargeintestinalcancercellsandstromalcells.Compar

6、edwithcoloncancer,colonicadenomaandnormaltissue,thepositiveexpressionratesofMMP-2inthestromalcellshavenosignificantdifferences(P>0.05),whilethedifferencewasclearinglandcells（P<0.05）.○4TheexpressionofMMP-2incolorectalcancerglandcellshasnocorrelationwithpatientfactorssuchas4万方数据华中科技大学

7、硕士学位论文age,genderandthepartofthetumor,butthereispositivelycorrelatedwiththemalignantdegreeofthetumor.○5Meanwhile,thestudyshowedthattheexpressionofSPARCinstromalcellswasnegativelycorrelatedwiththeexpressionofMMP-2intheglandcells(r=-0.465,P=0.000),buttheexpressionsinglandcellswerenotco

8、rrelated(r=0.156,P=