c实现枚举类型的++错误问题

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1、口袋中有红.黄.蓝.白.黑5种颜色球若干个。每次从口袋先后取出3个球，问得到3种颜色不同的球的可能,输出每种排列的情况。#includeenumColor{red,yellow,blue,white,black};intmain()enumColori,j,k,pri;intn」oop;n=0;for(i=red;i<=black;i++)//不能用i++,会报错for(j=red;j<=black;j++))if(i!=j)for(k=red;k<=black;k++)n=n+1;printfC%・4cTn);for(loop=1;lo

2、op<=3;loop++)switch(loop)case1:pri=i;break;sieala(Joe_q・「soT%=f£」dgoe_q0^3空ealqx=(D壬AV・・SOT%・匸uudgzM①se。空eaJa(=:・.soT%..mu一」2A/O_OA①se。三eaja(・・pal=・・sov%・・£u一」2pal①se。)(一」d)E_MS宀sie①」q二-nej①pYealq空"」d"①Seoueajq-ir一」d(N①Seo-K帑攀o>ss-llu①d

3、j—」++x£sod」0Jpaleo①p・au一)++」075」①do.ouuot山」届田(ou」n05」M5C一pg%_eocr)Jc匸d{F.UCJC匸d空wajq二-n3①p#includeenumColor{red,yellow,blue,white,black};intmain()enumColori,j,k,pri;intn,loop;n=0;for(i=red;i<=black;i=Color(i+1))//不能用i++,会报错for(j=red;j<=black;j=Color(j+1))if(i!=j)for(k=red

4、;k<=black;k=Color(k+1))if((k!=i)&&(k!=j)){n=n+1;printf(,,%-4dM,n);for(loop=1;loop<=3;loop++)switch(loop)case1:pri=i;break;case2:pri=j;break;case3:pri=k;break;default:break;}switch(pri){casered:printf("%-1Os","red");break;caseyellow:printf("%-10s","yellow,');break;caseblue:printf(H

5、%-1Os","blue");break;casewhite:printf(H%-1Os,,,',white");break;caseblack:printf("%-1Os”,”black“);b「eak;default:break;}}printf(”“)；}}printf("total:%5d",n);return0;42whiteyellowblack43vihitebluered44whiteblueyellow4Swhiteblueblack46whiteblackred47whiteblackyellow48whiteblackbl

6、ue49blackredyellow50blackredblue51blackredwhite52blackyellowred53blackyelloublue54blackyellowwhite5Sblackbluered56blackblueyellow57blackbluewhite58blackwhitered5$blackwhiteyellow60blackwhitebluetotal：60Processexitedafter0.06681secondswithreturnvalue0线