蔚西矿业公司低压供电保护整定书

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1、蔚西矿业公司低压供电电器整定书第一节短路电流计算一、掘进1000KVA变压器二次出口端的短路电流Id1计算变压器二次电压690V，容量1000KVA，系统短路容量按50MVA计算查表得，系统电抗0.0095Ω6KV电缆长度0.45km查表得R0=0.429Ω/kmX0=0.063Ω/km高压电缆电阻、电抗：Rg=0.429×0.45=0.19305ΩXg=0.063×0.45=0.02835Ω变压器电阻、电抗：Rb1=0.0029ΩXb1=0.0284ΩΣR=Rg/Kb²+Rb1=0.19305/8.69²+0.002

2、9=0.005456ΩΣX=ΣX=Xg+XX/Kb²+Kb1=0.02835+0.0095/8.69²+0.0284=0.028775ΩId1=Ue/2=4342A二、炮采区最末端22溜子的短路点Id2计算电缆电阻、电抗：3*50+1*160.16km查表得R0=0.448Ω/kmX0=0.081Ω/km3*25+1*100.05km查表得R0=0.616Ω/kmX0=0.081Ω/kmRZ1=0.448×0.16=0.07168ΩXZ1=0.081×0.16=0.01296ΩRZ2=0.616×0.05=0.0308

3、ΩXZ2=0.081×0.05=0.00405ΩΣR=Rg/Kb²+Rb1+RZ1+RZ2=0.107936ΩΣX=Xg/Kb²+Kb1+XZ1+XZ2=0.045785ΩId2=Ue/2=3136A一、掘一区最末端40溜子的短路点Id3计算电缆电阻、电抗：3*25+1*100.15km查表得R0=0.616Ω/kmX0=0.081Ω/kmRZ1=0.616×0.15=0.0924ΩXZ1=0.081×0.15=0.01215ΩΣR=Rg/Kb²+Rb1+RZ1=0.097856ΩΣX=Xg/Kb²+Kb1+XZ1=0

4、.040925ΩId3=Ue/2=3285A二、掘二区最末端煤电钻的短路点Id4计算电缆电阻、电抗：3*50+1*160.3km查表得R0=0.448Ω/kmX0=0.081Ω/km3*25+1*100.045km查表得R0=0.616Ω/kmX0=0.081Ω/kmRZ1=0.448×0.3=0.1344ΩXZ1=0.081×0.3=0.0243ΩRZ2=0.616×0.05=0.0308ΩXZ2=0.081×0.05=0.00405ΩΣR=Rg/Kb²+Rb1+RZ1+RZ2=0.170656ΩΣX=Xg/Kb²+

5、Kb1+XZ1+XZ2=0.057125ΩId4=Ue/2=1924A一、综采双速最末端水泵的短路点Id5计算电缆电阻、电抗：3*25+1*100.5km查表得R0=0.616Ω/kmX0=0.081Ω/kmRZ1=0.616×0.5=0.308ΩXZ1=0.081×0.5=0.0405ΩΣR=Rg/Kb²+Rb1+RZ1=0.313456ΩΣX=Xg/Kb²+Kb1+XZ1=0.069275ΩId5=Ue/2=1078A二、机运500KVA变压器二次出口端的短路电流Id6计算变压器二次电压690V，容量500KVA，

6、系统短路容量按50MVA计算查表得，系统电抗XX=0.0095Ω6KV电缆长度0.01km查表得R0=0.429Ω/kmX0=0.063Ω/km高压电缆电阻、电抗：Rg=0.429×0.01=0.00429ΩXg=0.063×0.01=0.00063Ω变压器电阻、电抗：Rb1=0.0068ΩXb1=0.0427ΩΣR=Rg/Kb²+Rb1=0.00429/8.69²+0.0068=0.000056ΩΣX=Xg+XX/Kb²+Kb1=0.00063+0.0095/8.69²+0.0427=0.000131ΩId6=Ue/

7、2=4832A机运区最末端25绞车的短路点Id7计算电缆电阻、电抗：3*50+1*160.16km查表得R0=0.448Ω/kmX0=0.081Ω/km3*25+1*100.05km查表得R0=0.616Ω/kmX0=0.081Ω/kmRZ1=0.448×0.16=0.07168ΩXZ1=0.081×0.16=0.01296ΩRZ2=0.616×0.05=0.0308ΩXZ2=0.081×0.05=0.00405ΩΣR=Rg/Kb²+Rb1+RZ1+RZ2=0.107936ΩΣX=Xg/Kb²+Kb1+XZ1+XZ2=

8、0.045785ΩId7=Ue/2=2450A一、掘进1000KVA变压器二次出口端的短路电流Id8计算变压器二次电压690V，容量1000KVA，系统短路容量按50MVA计算查表得，系统电抗0.0095Ω6KV电缆长度0.45km查表得R0=0.429Ω/kmX0=0.063Ω/km高压电缆电阻、电抗：Rg=0.429×0.45