c++课后习题解答

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1、C++课后习题程序3-14.用递归的方法编写程序求N阶勒让德多项式的值，在主程序中实现输入输出。递归公式为1(n=0)Pn(x)=x(n=1)[(2n-1)x*Pn-1(x)-(n-1)Pn-2(x)]/n(n>1)#includeusingnamespacestd;longp(intx,inty)//Legendrepolynomials函数定义{if(y==0)return1;elseif(y==1)returnx;elsereturn(((2*y-1)*x*p(x,y-1)

2、-(y-1)*p(x,y-2))/y);}voidmain(){inta;//legendrepolynomials函数中x的值intn;//级数ncout<<"请输入legendrepolynomials函数中x的值：";cin>>a;cout<<"请输入所要求的多项式级数：";cin>>n;p(a,n);cout<<"n阶勒让德多项式的值为(当x="<

3、，以及对这些属性操作的方法。实现并测试这个类。(第一个程序待调试)???#includeclassDog{public:Dog(intinitialAge=0，intinitialWeight=5);~Dog();intGetAge(){returnitsAge;}//inline!voidSetAge(intage){itsAge=age;}//inline!intGetWeight(){returnitsWeight;}//inline!voidSetWeight(int

4、weight){itsAge=weight;}//inline!private:intitsAge，itsWeight;};Dog::Dog(intinitialAge，intinitialWeight){itsAge=initialAge;itsWeight=initialWeight;}Dog::~Dog()//destructor，takesnoaction{}intmain(){DogJack(2，10);cout<<"JackisaDogwhois";cout<

5、<<"yearsoldand";cout<#includeusingnamespacestd;c

6、lassdog{private:intm_age;intm_weight;public:dog():m_age(5),m_weight(10){}voidsetAge(inti){m_age=i;}voidsetWeight(inti){m_weight=i;}intage(){returnm_age;}intweight(){returnm_weight;}};intmain(){dogd;cout<

7、个名为Rectangle的矩形类，其属性为矩形的左下角与右上角两个点的坐标，能计算矩形的面积。#includeclassRectangle{public:Rectangle(inttop,intleft,intbottom,intright);~Rectangle(){}intGetTop()const{returnitsTop;}intGetLeft()const{returnitsLeft;}intGetBottom()const{returnitsBottom;}int

8、GetRight()const{returnitsRight;}voidSetTop(inttop){itsTop=top;}voidSetLeft(intleft){itsLeft=left;}voidSetBottom(intbottom){itsBottom=bottom;}voidSetRight(intright){itsRight=right;}intGetArea()const;private:intitsTop;intitsLeft;intitsBot