120425程序设计题练习

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1、【程序设计1】：功能：求1到100之间的偶数之积[3]。1：#include2：voidwwjt();3：doublefun(intm)4：{/********Program**********/5：6：7：/********End**********/}8：9：Main()10：{printf(“ji=%f”,fun(100));11：wwjt();}1voidwwjt();{FILE*IN,*OUT;IntiIN,i;doubledOUT;IN=fopen(“in.dat”,”r”);if(IN==NULL){printf(“PleaseVerifyTheCur

2、rerntDir..itMayBeChanged”);}OUT=fopen(“out.dat”,”w”);if(OUT==NULL){printf(“PleaseVerifyTheCurrerntDir..itMayBeChanged”);}2if(OUT==NULL){printf(“PleaseVerifyTheCurrerntDir..itMayBeChanged”);}for(i=0;i<5;i++){fscan(IN,”%d”,&iIN);dOUT=fun(iIN);fprintf(OUT,”%f”,dOUT);}fclose(IN);fclose(OUT);}3【程序设计

3、1】：功能：求1到100之间的偶数之积[3]。答案：doubley=1;inti;for(i=1;i<=n;i++)if(i%2==0)y*=i;returny;4【程序设计2】：用while语句求1～100的累计和(377)。1：#include2：voidwwjt();3：intfun(intn)4：{/**********Program**********/5：6：7：8：/**********End**********/}9：voidmain():10：{intsum=0;11：sum=fun(100);12：printf(“sum=%d”,sum);13：

4、wwjt();}5voidwwjt(){FILE*IN,*OUT;inti;intiIN,iOUT;IN=fopen("in.dat","r");if(IN==NULL){printf("PleaseVerifyTheCurrerntDir..itMayBeChanged");}OUT=fopen("out.dat","w");if(OUT==NULL){printf("PleaseVerifyTheCurrentDir..itMayBeChanged");}for(i=0;i<5;i++){fscanf(IN,"%d",&iIN);iOUT=fun(iIN);fprintf(OUT,"

5、%d",iOUT);}fclose(IN);fclose(OUT);}6【程序设计2】：用while语句求1～100的累计和。答案：intsum=0,i=0;while(i<=n){sum=sum+i;i++;}returnsum;7【程序设计3】编写函数求3!+6!+9!+12!+15+18!+21!。1:#include2:voidwwjt();3:floatsum(intn)4:{/**********Program**********/5:6:7:8:/**********End**********/}9:main()10:{11:printf("thiss

6、um=%e",sum(21));12:wwjt();}8voidwwjt(){FILE*IN,*OUT;inti;intiIN,iOUT;IN=fopen("in.dat","r");if(IN==NULL){printf("PleaseVerifyTheCurrerntDir..itMayBeChanged");}OUT=fopen("out.dat","w");if(OUT==NULL){printf("PleaseVerifyTheCurrentDir..itMayBeChanged");}for(i=0;i<5;i++){fscanf(IN,"%d",&iIN);iOUT=f

7、un(iIN);fprintf(OUT,"%d",iOUT);}fclose(IN);fclose(OUT);}9【程序设计3】：功能：编写函数求3!+6!+9!+12!+15!+18!+21!。答案：inti,j;floatt,s=0;for(i=3;i<=n;i=i+3){t=1;for(j=1;j<=i;j++)t=t*j;s=s+t;}returns;10【程序设计4】功能：求一个给定字符串中的字母的个数。1:#incl