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1、基础工程课程习题第二章浅基础2.1地基承载力计算beconsistentwithinthesamedisk.Alternateunifiedcorerequirementsplacedontheterminalstripterminals,onlineidentityandensurethecoppercoreisnotexposed.6.4.6enclosurewithinthesametothecablecoreprovidesbindingintoacircle,harnesstiespaci
2、ngisgenerally100mm;branchofficesshallbebindingonbothends,eachcorebeconsistentwithinthesamedisk.Alternateunifiedcorerequirementsplacedontheterminalstripterminals,onlineidentityandensurethecoppercoreisnotexposed.6.4.6enclosurewithinthesametothecablecorep
3、rovidesbindingintoacircle,harnesstiespacingisgenerally100mm;branchofficesshallbebindingonbothends,eachcore2.2基础底面尺寸【例7-2】某柱下矩形单独基础。已知按荷载效应标准组合传至基础顶面的内力值Fk=920kN,Vk=15KN,MK=235KN.m；地基为粉质粘土，其重度为γ=18.5KN/m3,地基承载力特征值fak=180kPa(ηb=0.3,ηd=1.6)基础埋深d=1.2m，试确定基
4、础地面尺寸。§【解】（1）求修正后的地基承载力特征值§假定基础宽度b<3m,则（2）初步按轴心受压基础估算基底面积考虑偏心荷载的影响，将底面积A0增大20%，则A=5.2×1.2=6.24m2。取基底长短边之比l/b=2，得，取b=1.8m,l=3.6m。（3）验算地基承载力基础及其台阶上土重基底处力矩偏心矩基底边缘最大压力beconsistentwithinthesamedisk.Alternateunifiedcorerequirementsplacedontheterminalstripter
5、minals,onlineidentityandensurethecoppercoreisnotexposed.6.4.6enclosurewithinthesametothecablecoreprovidesbindingintoacircle,harnesstiespacingisgenerally100mm;branchofficesshallbebindingonbothends,eachcore满足要求，故基底尺寸长l=3.6m,b=1.8m合适。【例】墙下条形基础在荷载效应标准值组合时，
6、作用在基础顶面上的轴向力Fk=280kN/m,基础埋d=1.5m,室内外高差0.6m，地基为黏土（ηb=0.3,ηd=1.6)，其重度γ＝１８kN/m3,地基承载力特征值fak=150kPa求该条形基础宽度。【解】（1）求修正后的地基承载力特征值假定基础宽度b<3m,因埋深d>0.5m，故进行性地基承载力深度修正。（2）求基础宽度因为室内外高差0.6m，故基础自重计算高度基础宽度：取b=2m，由于与假定相符，最后取b=2mbeconsistentwithinthesamedisk.Alternate
7、unifiedcorerequirementsplacedontheterminalstripterminals,onlineidentityandensurethecoppercoreisnotexposed.6.4.6enclosurewithinthesametothecablecoreprovidesbindingintoacircle,harnesstiespacingisgenerally100mm;branchofficesshallbebindingonbothends,eachco
8、re2.3基础沉降beconsistentwithinthesamedisk.Alternateunifiedcorerequirementsplacedontheterminalstripterminals,onlineidentityandensurethecoppercoreisnotexposed.6.4.6enclosurewithinthesametothecablecoreprovidesbindingintoacircle,harnesstiespac
