小学六年级解比例及解方程练习题

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1、人教版六年级解方程及解比例练习题解比例:x:10=:0.4:x=1.2:2=:=:x0.8:4=x:8:x=3:121.25:0.25=x:1.6==constructionqualityacceptanceandassessmentRegulation(ProfessionalEdition)(DL/T5210.2-2009~DL/T5210.8-2009);1.9thequalitycheckoutandevaluationofelectricequipmentinstallationengineeringcode(DL/

2、T5161.1-2002~5161.17-2002);1.10thenormsofconstructionsupervision,theelectricpowerconstructionsupervisionregulationsx:=6:=45:x=18:262.8:4.2=x:9.6:x=:2.8:4.2=x:9.6x:24=:8:x=::=x:constructionqualityacceptanceandassessmentRegulation(ProfessionalEdition)(DL/T5210.2-2009~

3、DL/T5210.8-2009);1.9thequalitycheckoutandevaluationofelectricequipmentinstallationengineeringcode(DL/T5161.1-2002~5161.17-2002);1.10thenormsofconstructionsupervision,theelectricpowerconstructionsupervisionregulations0．6∶4＝2.4∶x　　　6∶x＝∶＝∶＝x∶∶＝∶xx∶＝0.7∶10∶50＝x∶40　　　1.

4、3∶x＝5.2∶20x∶3.6＝6∶18∶＝∶x＝＝解方程X－X=2X+=70%X+20%X=3.6X×=20×25%+10X=X-15%X=68X＋X＝1215X－3×＝X÷＝12constructionqualityacceptanceandassessmentRegulation(ProfessionalEdition)(DL/T5210.2-2009~DL/T5210.8-2009);1.9thequalitycheckoutandevaluationofelectricequipmentinstallationeng

5、ineeringcode(DL/T5161.1-2002~5161.17-2002);1.10thenormsofconstructionsupervision,theelectricpowerconstructionsupervisionregulations6X＋5=13.43X=X÷=X＋X=4X－6×=2÷X=X=X=×X÷=×4x－3×9=29x+x=4X－21×=46X＋5=13.4X-X=4χ－6＝38constructionqualityacceptanceandassessmentRegulation(Pro

6、fessionalEdition)(DL/T5210.2-2009~DL/T5210.8-2009);1.9thequalitycheckoutandevaluationofelectricequipmentinstallationengineeringcode(DL/T5161.1-2002~5161.17-2002);1.10thenormsofconstructionsupervision,theelectricpowerconstructionsupervisionregulations5X=X=X÷=X÷=12X=X

7、=×X÷=÷X-0.25==30%4+0.7X=102X+X=42X+X=105X-X=400X-0.125X=8=constructionqualityacceptanceandassessmentRegulation(ProfessionalEdition)(DL/T5210.2-2009~DL/T5210.8-2009);1.9thequalitycheckoutandevaluationofelectricequipmentinstallationengineeringcode(DL/T5161.1-2002~5161

8、.17-2002);1.10thenormsofconstructionsupervision,theelectricpowerconstructionsupervisionregulationsX+X=18X×(+)=x－0.375x=x×+=4×X－X＝12　　　　5X－