电工学复习题上册(1)

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1、1.用支路电流法求图1.10中各支路电流。IS10V2W5AR2I2I1R1US+_3W图1.10解：列方程：解得：2.用叠加原理求上图1.10所示电路中的电流I1和I2。loanapprovalandpostcreditapprovalofficer/atalllevelsinaccordancewithcreditapprovalrules,licensingandeventualexerciseofcreditdecisionpowerofpersonsorinstitutions.Reviewfindingsandreviewcomments,accordingtotheBank

2、'scredit解：恒流源单独作用时：恒压源单独作用时：恒流源与恒压源共同作用时：3.用戴维宁定理求上图1.10所示电路中的电流I2.。解：4.用诺顿定理求上图1.10所示电路中的电流I2。解：5.在下图所示电路中，开关S闭合前电路已处于稳态，试确定S闭合后电压uC和电流iC、i1、i2的初始值和稳态值。loanapprovalandpostcreditapprovalofficer/atalllevelsinaccordancewithcreditapprovalrules,licensingandeventualexerciseofcreditdecisionpowerofpers

3、onsorinstitutions.Reviewfindingsandreviewcomments,accordingtotheBank'scredit解：(1)求初始值(2)求稳态值6.在下图所示电路中，开关S闭合前电路已处于稳态，试确定S闭合后电压uL和电流iL、i1、i2的初始值和稳态值。loanapprovalandpostcreditapprovalofficer/atalllevelsinaccordancewithcreditapprovalrules,licensingandeventualexerciseofcreditdecisionpowerofpersonsori

4、nstitutions.Reviewfindingsandreviewcomments,accordingtotheBank'scredit解：(1)求初始值loanapprovalandpostcreditapprovalofficer/atalllevelsinaccordancewithcreditapprovalrules,licensingandeventualexerciseofcreditdecisionpowerofpersonsorinstitutions.Reviewfindingsandreviewcomments,accordingtotheBank'scredi

5、t(2)求稳态值7.下图所示电路原已处于稳态，在t=0时，将开关S断开，试用三要素法求换路后的uC和iC。loanapprovalandpostcreditapprovalofficer/atalllevelsinaccordancewithcreditapprovalrules,licensingandeventualexerciseofcreditdecisionpowerofpersonsorinstitutions.Reviewfindingsandreviewcomments,accordingtotheBank'scredit解：8．已知某负载的电流和电压的有效值和初相位分别

6、是2A、－；36V、,频率均为50Hz。(1)写出它们的瞬时值表达式；(2)画出它们的波形图；(3)指出它们的幅值、角频率以及二者之间的相位差。解：（1）（2）波形如图所示：loanapprovalandpostcreditapprovalofficer/atalllevelsinaccordancewithcreditapprovalrules,licensingandeventualexerciseofcreditdecisionpowerofpersonsorinstitutions.Reviewfindingsandreviewcomments,accordingtotheBan

7、k'scredit（3）电流幅值，电流角频率314rad/s，电压幅值，电压角频率314rad/s，电压与电流的相位差（u超前于i）3.2.2已知A=8+j6，。求（1）A＋B；（2）A－B；（3）；（4）；（5）jA＋B；（6）。解：（1）（2）（3）（4）（5）loanapprovalandpostcreditapprovalofficer/atalllevelsinaccordancewithcreditapprovalrul