2011年9月二c上机编程题答案

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1、本答案仅供参考（请不要随意更改）A类数学表达式（1—10）（N）1#include#includefloatfun(intm,intn){floatt1=1,t2=1,t3=1,i;for(i=1;i<=m;i++)t1*=i;for(i=1;i<=n;i++)t2*=i;for(i=1;i<=m-n;i++)t3*=i;returnt1/(t2*t3);}main(){printf("P=%f",fun(12,8));}2#include

2、>#include#includefloatfun(){floatx1=0.0,x0;x0=x1;x1=cos(x0);while(fabs(x0-x1)>=0.000001){forthequalityofreviewsandreview.Article26threview(a)theCCRAcompliance,whethercopiesofchecks;(B)whetherdoubleinvestigation;(C)submissionofprogram

3、compliance,investigationorexaminationofwhetherviewsareclear;(D)theborrower,guarantorloansx0=x1;x1=cos(x0);}returnx1;}main(){printf("Root=%f",fun());}3#include#includedoublefun(intn){doublef0=0,f1=1,fn;fn=f0+f1;while(fn<=n){f0=f1;f

4、1=fn;fn=f0+f1;}returnfn;}main()/*主函数*/{printf("%f",fun(1000));}4#include#includevoidfun(float*sn,intn){forthequalityofreviewsandreview.Article26threview(a)theCCRAcompliance,whethercopiesofchecks;(B)whetherdoubleinvestigation;(C)su

5、bmissionofprogramcompliance,investigationorexaminationofwhetherviewsareclear;(D)theborrower,guarantorloansfloati,t=1;*sn=0;for(i=0;i<=n;i++){*sn+=t/(2*i+1);t=-t;}}main()/*主函数*/{intn=11;floats;fun(&s,n);printf("s=%fn=%d",s,n);}5#include#inc

6、lude#includedoublefun(intm){doubles=0，i;for(i=1;i<=m;i++)s+=log(i);returnsqrt(s);}main(){printf("%f",fun(20));}forthequalityofreviewsandreview.Article26threview(a)theCCRAcompliance,whethercopiesofchecks;(B)whetherdoubleinvestigatio

7、n;(C)submissionofprogramcompliance,investigationorexaminationofwhetherviewsareclear;(D)theborrower,guarantorloans6#include#include#includedoublefun(doublex,intn){doubles=x+1,i,t=1;for(i=2;i<=n;i++){t*=i;s+=pow(x,i)/t;}return

8、s;}main(){printf("%f",fun(0.3,10));}7#include#includedoublefun(intn){doubles=0,i;for(i=1;i<=n;i++)s+=1.0/(i*(i+1));returns;}main(){forthequalityofreviewsandreview.Article26threview(a)theCCRAcompliance,whethercopiesofchecks;(B)wheth