哈工大理论力学第七版课后习题答案完整版

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1、哈工大理论力学第七版课后习题答案完整版1第1章静力学公理和物体的受力分析1-1画出下列各图中物体A，ABC或构件AB，AC的受力图。未画重力的各物体的自重不计，所有接触处均为光滑接触。PFN2FN1A(a)(a1)PFNAFT(b)(b1)PBAN2FN3FN1F(c)(c1)ABP2P1FAxFAyFT(d)(d1)FBFAFAB(e)(e1)2ABFFAxBFFAyq(f)(f1)ABFCCFAF(g)(g1)ACP1CFFAxFAyB2P(h)(h1)BFCFAxADCFAyF(i)(i1)(j)(j1

2、)ABCPAxFAyFBFF(k)(k1)3CAFCAFACFBAFABBAPFA′CFA′B(l)(l1)(l2)(l3)图1-11-2画出下列每个标注字符的物体的受力图。题图中未画重力的各物体的自重不计，所有接触处均为光滑接触。N2FP2CNF′(a)(a1)P1N1FN2FFAxFAy2PCAB1PN1FFAxANFBAyF(a2)(a3)2P1PN1AFN3FN2FB(b)(b1)1PN1AFNFP2N3FNF′N2FB(b2)(b3)4BN1FAP2AxFAyFDCN2F1P(c)(c1)P1BN1

3、FDN2FFTAP2AxFAyFFT′(c2)(c3)ACDBCFFAyqFBFAx(d)(d1)ACDCFFAyqFAxDyFDxFDBqFBDxF′DyF′(d2)(d3)ABCPqAxFAyFFCyFCxABqAxFAyFBxFByFBCxCPFCyFBxF′FB′y(e)(e1)(e2)(e3)CABF2FByFAxFBxFAyF1(f)(f1)5CAFAxFAy1FFCxFCyCBF2FByFBxFC′xFC′y(f2)(f3)PBFAyFAxAFCB(g)(g1)BAyFFAxFACBTFCxFD

4、PCCxF′CyF′TF(g2)(g3)BAxFAyFABF′1FDCxBFCyFCBF2F(h)(h1)(h2)AOCOyFOxFCxFCyFAxFAyFCDCyFF′CxF′EAFBE(i)(i1)(i2)6AOBCOyFOxFBxFByFDFEABBxFByFEF′AxF′AyF′(i3)(i4)ABCHDEPAyFAxFBxFByFBCByFBxFCyFCxFTF(j)(j1)(j2)DT2FT1FDyFDxFT2EF′T3FExFEyFADAxFAyFDyF′DxF′ECCyF′CxF′ExF′Ey

5、F′(j3)(j4)(j5)BBFCFDEF′CyF′CxF′Eθ(k)(k1)ABBFCFAyFAxFEDθACyFCFAyFAxFDEFCxFD90°.θ(k2)(k3)DE7ABAFBFCFCBDDF1FBF′(l)(l1)(l2)EEF2FDDF′ABCDE1F2FAFCFEF(l3)(l4)或BCCFDyFDxF1FBF′DDEDyF′EyFExFDxF′2FABCDE21FFAFCFEyFExF(l2)’(l3)’(l4)’CCyF1FCxFBAADF′(m)(m1)EFEADFDHFH2FADF

6、ADF′AD(m2)(m3)8BOAOxFOyFNBFNAFkF(n)(n1)DqN1FN3FN2FBF′B(n2)BDGFACEAFCFEFFGF(o)(o1)BABFAFBDCFDFBF′CDEFFDFF′FFE(o2)(o3)(o4)图1-29第2章平面汇交力系与平面力偶系2-1铆接薄板在孔心A，B和C处受3个力作用，如图2-1a所示。100N1F=，沿铅直方向；50N3F=，沿水平方向，并通过点A；50N2F=，力的作用线也通过点A，尺寸如图。求此力系的合力。3F1FRFcdba2Fθy3xF21FF

7、60A(a)(b)(c)图2-1解（1）几何法作力多边形abcd，其封闭边ad即确定了合力FR的大小和方向。由图2-1b，得2322R12F=(F+F×4/5)+(F+F×3/5)=(100N+50N×4/5)2+(50N+50N×3/5)2=161N(,)arccos(4/5)R12R1FF+F×∠FF=)29.742944161Narccos(100N50N4/5==′+×=oo（2）解析法建立如图2-1c所示的直角坐标系Axy。3/550N50N3/580N12ΣF=F+F×==+×=x4/5100N5

8、0N4/5140N12ΣF=F+F×=+×=y(80140)NRF=i+j(80N)2(140N)2161NRF=+=2-2如图2-2a所示，固定在墙壁上的圆环受3条绳索的拉力作用，力F1沿水平方向，力F3沿铅直方向，力F2与水平线成40°角。3个力的大小分别为F1=2000N，F2=2500N，F3=1500N。求3个力的合力。3F1F2F40°yxO(a)(b)(c)图2-2解（1）解析法建立如