1、一、程序阅读:1、Programex1;Vara,b,c,p,q:integer;r:array[0..2]ofinteger;beginread(a,b,c);p:=adivbdivc;q:=b-c+a+p;r[0]:=a*pdivq*q;r[1]:=r[0]*(r[0]-300);if(3*q-pmod3<=r[0])and(r[2]=r[2])thenr[1]:=r[r[0]divpmod2]elser[1]:=qmodp;writeln(r[0]-r[1]);end.输入:10073输出结果:_____________________。2、programchu2; vari
2、,j,f:integer; a:array[1..8]ofinteger; begin fori:=1to8do begin f:=imod2; iff=0thena[i]:=0 elsea[i]:=1; forj:=1toido iff=0thena[i]:=a[i]+j elsea[i]:=a[i]*j end; fori:=1to8do write(a[i]:5);end. 输出:3、programchu3;vara:array[1..6]of integer; i,j,p,t:integer;be
3、gin fori:=1tondoread(a[i]); forj:=1ton-1do begin p:=j; fori:=jtondo if a[i]