资源描述：
《水文学原理与水文测试上机》由会员上传分享，免费在线阅读，更多相关内容在行业资料-天天文库。
1、水文分析计算1、某枢纽处实测21年最大洪峰流量资料如下表，根据配线法计算P=1%和15%洪峰流量童晟年份洪峰流量Qi（m3/s）序号由大到小排列Qi（m3/s）模比系数KiKi-1(Ki-1)2P=m/(n+1)×100%<1><2><3><4><5><6><7><8>19451540127502.141.141.29964.551946980223901.860.860.73969.1019471090318601.450.450.202513.6419481050417401.360.360.129618.181
2、9491860515401.200.200.0422.7319501140615201.180.180.032427.271951790712700.99-0.010.000131.8219522750812600.98-0.020.000436.361953762912100.94-0.060.003640.91195423901012000.94-0.060.003645.45195512101111400.89-0.110.012150.0195612701210900.85-0.150.022554.5519
3、5712001310500.82-0.180.032459.09195817401410500.82-0.180.032463.641959883159800.76-0.240.057668.1819601260168830.69-0.310.096172.731961408177940.62-0.380.144477.2719621050187900.62-0.380.144481.8219631520197620.59-0.410.168186.361964483204830.38-0.620.384490.91
4、1965734214080.32-0.680.462495.45步骤：1.将每年年份与对应洪峰流量以对应的格式输入TXT文档，保存。2.用A软件运行该文档得到下图1。3.在TXT文档里输入无最大值数据格式的数据，保存到相应位置，运行PLQX软件，可得到根据数据拟合出的P-III型曲线，见图2。由PLQX计算成果可得洪峰流量为3545.101时，P=1%，洪峰流量为1917.034时，P=15%。4.根据PLQX软件得到的数据可以计算相关表格中的数据。A软件运行后得到的适线图图1P-III型曲线图图23.某流域一场降雨
5、产生三个时段净雨，且已知流域△t=6h的单位线，见下表，试推求出口端面流量过程时间（日，时）地面净雨h(mm)单位线q(t)(m³/s)部分地面径流h/10q(t)地面径流Qs(t)(m³/s)地下径流Qg(t)(m³/s)出口断面流量过程Q(t)(m³/s)h1=19.7h2=9.0h3=7.0238 0000020201419.7440000242420918286.680086.6824110.682427333358.5439.60398.1424422.148 281656.01163.830.8850.6
6、130880.6114 226553.57299.7127.4980.67301010.6720 156445.22252.9233.1931.2230961.22252 121307.32203.4196.7707.4226733.428 83238.37140.4158.2536.9726562.9714 60163.51108.9109.2381.6126407.6120 40118.274.784.7277.626303.6262 2378.85458.1190.924214.98 1145.31364212
7、3.3124147.3114 621.6720.72870.372494.3720 411.829.916.137.822259.82272 07.885.47.720.982242.988 03.64.27.82027.814 02.82.82022.8 00 0步骤：1.在VisualC++中编写程序如下：#includevoidmain(){floatq[18]={0,44,182,333,281,226,156,121,83,60,40,23,11,6,4,0,0,0};flo
8、atp[18]={20,24,24,24,30,30,30,26,26,26,26,24,24,24,22,22,20,20};floatz[18];floata,b,c;inti;scanf("%f%f%f",&a,&b,&c);z[0]=p[0];z[1]=a/10*q[0]+p[1];z[2]=a/10*q[1]+b/10*q[0]+p[
