节约里程法matlab

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1、clearclcA=[015510520;0303020510;08516226140110];rong=300;m=6;c=zeros(6,6);fori=1:mforj=1:mc(i,j)=sqrt((A(1,i)-A(1,j))^2+(A(2,i)-A(2,j))^2);endendp=zeros(6,6);fori=2:(m-1)forj=(i+1):mp(i,j)=c(1,i)+c(1,j)-c(i,j);endends=p(:);[hs,wz]=sort(s,1,'descend');

2、fori=1:(m^2)[x,y]=ind2sub(size(p),wz(i));ifA(3,x)+A(3,y)<=rongsolut=[x,y];n(1)=2;zhuang(1)=A(3,x)+A(3,y);ii=i;breakelsecontinueendendforrr=(ii+1):(m^2)[x,y]=ind2sub(size(p),wz(rr))ifhs(rr)==0breakend[xa,ya]=find(x==solut)[xb,yb]=find(y==solut)[sa,sb]=

3、size(solut)ifisempty(xa)==0&&isempty(xb)==0ifxa==xbcontinueendifn(xa)~=2if1

4、seifya==1&&yb==n(xb)newm=[solut(xb,1:n(xb))solut(xa,1:n(xa))]elseifya==n(xa)&&yb==1newm=[solut(xa,1:n(xa))solut(xb,1:n(xb))]elseifya==n(xa)&&yb==n(xb)newm=[solut(xa,1:n(xa))solut(xb,n(xb):-1:1)]endsolut(xa,:)=[]solut(xb,:)=[]n(xa)=[]n(xb)=[]zhuang(xa)

5、=[]zhuang(xb)=[][qa,qb]=size(solut)solut((qa+1),1:length(newm))=newmn(qa+1)=length(newm)zhuang(qa+1)=zh1+zh2elsecontinueendelseifisempty(xa)==0ifn(xa)~=2if1

6、(xa))]elseifya==n(xa)newm=[solut(xa,1:n(xa))y]endsolut(xa,:)=[]n(xa)=[]zhuang(xa)=[][qa,qb]=size(solut)solut((qa+1),1:length(newm))=newmn(qa+1)=length(newm)zhuang(qa+1)=zh3endelseifisempty(xb)==0ifn(xb)~=2if1

7、)ifzhuang(xb)+A(3,x)<=rongifyb==1newm=[xsolut(xb,1:n(xb))]elseifyb==n(xb)newm=[solut(xb,1:n(xb))x]endsolut(xb,:)=[]n(xb)=[]zhuang(xb)=[][qa,qb]=size(solut)solut((qa+1),1:length(newm))=newmn(qa+1)=length(newm)zhuang(qa+1)=zh4endelsezh5=A(3,x)+A(3,y)ifz

8、h5<=rongnewm=[xy][qa,qb]=size(solut)solut((qa+1),1:length(newm))=newmn(qa+1)=length(newm)zhuang(qa+1)=zh5endendendifsum(n)<(m-1)fori=2:m[qqqa,qqqb]=size(solut)kk=find(i==solut)ifisempty(kk)solut(qqqa+1,1)=in(qqqa+1)=1zhuang(qqqa+1)=A(3,i)enden