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1、物理学教程(第二版)上册习题答案第一章 质点运动学1-1 质点作曲线运动,在时刻t质点的位矢为r,速度为v,速率为v,t至(t+Δt)时间内的位移为Δr,路程为Δs,位矢大小的变化量为Δr(或称Δ|r|),平均速度为,平均速率为.(1)根据上述情况,则必有( )(A)|Δr|=Δs=Δr(B)|Δr|≠Δs≠Δr,当Δt→0时有|dr|=ds≠dr(C)|Δr|≠Δr≠Δs,当Δt→0时有|dr|=dr≠ds(D)|Δr|≠Δs≠Δr,当Δt→0时有|dr|=dr=ds(2)根据上述情况,则必有( )(A)||=,||= (B)||≠,||≠(C)||=,
2、||≠(D)||≠,||=分析与解 (1)质点在t至(t+Δt)时间内沿曲线从P点运动到P′点,各量关系如图所示,其中路程Δs=PP′,位移大小|Δr|=PP′,而Δr=|r|-|r|表示质点位矢大小的变化量,三个量的物理含义不同,在曲线运动中大小也不相等(注:在直线运动中有相等的可能).但当Δt→0时,点P′无限趋近P点,则有|dr|=ds,但却不等于dr.故选(B).(2)由于|Δr|≠Δs,故,即||≠.但由于|dr|=ds,故,即||=.由此可见,应选(C).loanmanagement(post)review:1,approvalcriteriahave
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7、editlinestobecancelled.Borrowersignature:date-unusedcreditlines,agreetowriteoffloans.-Creditloanprincipalrepayment,agreetowriteoffloans.CustomerManagersignature:1-2 一运动质点在某瞬时位于位矢r(x,y)的端点处,对其速度的大小有四种意见,即(1); (2); (3); (4).下述判断正确的是( )(A)只有(1)(2)正确 (B)只有(2)正确(C)只有(2)(3)正确(D)只有(3)(4)
8、正确分析与