2022年浙江省湖州高考考前提分化学仿真卷含解析

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2C.·¸ᵯ/ḄÆ᩽STUFMH+OH--2e-=M*+H2஺D.ᐙᵯ᜜ᵯÈ[{NO2moiᵯ'N᩽²,ᡂImolSᓫÊ8ஹᑡ?@ḄA.᪗¨ËÌ5.6LᵫCH,kC2H4¶ᡂḄÎᔠÏÃ[ᨵḄ·¡'ᦪÐÑF6.02X1023B.CO(g)+HO(g)F^CO(g)+H(g)AH==-41kJ/mol,Òᨵ2moicOÓÔST¬STAHÕᡂ¡ᩭḄ2Ö222C.ST2NaCl(s)==2Na(s)+CL(g)ḄAHVO,AS>0D.ÔᐭAl¾HzḄ×[gNO-,K+,SO?",Mg?+ᜧÚᐳÜ39ஹÝÃÞ×[ßᑖ&ᐹᨵ,âãᦔTḄᓄæᱥÊçèé⏚êIèé⏚Ḅ᪀©U᝞<ᡠ>஺ᑡᨵᐵ?@ḄA.ᑖ'[ᨵ2ìíîB.ᔳðé⏚ñò²ḄóôõᱥᐳᨵöìC.1mol÷|ᗟé⏚kúÚ·Ï,STᨬmüὑ5molH2D.ᑖ'[þÿឋ
10ஹ┞ᧇᵯ(᝞)ஹᡂᵯᩖḄῖ⇨“#$”&'ᵯ(ᐸ*+ᵯ,-.2Li+Cu2O+H2O=2Cu+2Li++2OH-,/ᑡ12┯4Ḅ5A.᦮789,*:ᓄᑺ-02B.+ᵯ=>᩽Ḅᵯ᩽89@-.Cu2O+HO+2e=2Cu+2OH2C.+ᵯ=AᵯB*0.1molᵯḄᵯ=ᨵ0DmolLi+EFGᵯHIᔣCu᩽KLᨵ᪗NOP/1.12L:QR89D.=Sῖ⇨⊤☢&'Cm஺11ஹᓄWR'&ஹ'XYZ[\ᑗ^ᐵ஺/ᑡᨵᐵ12>`Ḅ5()A.abc*+dḄCaOe■gab:ᓄhIB.i-jkl980mnopẆrḄ7msᱏuvsᱏḄp⌕ᡂᑖ5y:ᓄấC.{|}~eᦔᙢ◀SG*ḄPb2+ஹCu2\Cd2\Hg2+ᐸI5{|}~

3Ḅᱥᳮᔾ▬D.SO2ᐹᨵឋeᵨᩭஹஹஹ₝12ஹ¡'ᱥᧇᵯ5ᢣᙠ¡'ᱥḄ¤ᵨ/¥ᓄW¦§ᓄ-ᵯ¦Ḅ¨d©¡'ᱥᧇᵯḄª¤ᳮ᝞ᡠ¬/ᑡ12┯4Ḅ5Iᣚ¯A.bᵯ᩽r'°89.4H++O2+4e=2HO2B.ᵯB*ᨵ4moiᵯr'§Kᜧ²³ὑ᪗NOP/22.4LC.µᢝ·¸¹ºᙠ¨d»¦ᢝ¼¥ᨵ½ᱥ:ᓄᡂCCh¾&'ᵯD.HS-ᙠ¿:ᓄ¹¤ᵨ/§ᓄ-S0Ḅ895HS+4HO-8e=SO+9H+213ஹᓄWÀWÁÂÃ'XIYÄÅZ[rÆᐹᨵ⌕¤ᵨ஺/ᑡ12>`Ḅ5()A.©ÇᐗÉḄᯚ⁐89ஹÌÁÍஹ᯼ḄᓄஹÏÐḄÑᓄÒ5ᓄWhᓄḄ,B.Ó:ᓄᱥḄᜧ᣸+[ÕÖᐝᓄWØÙஹ⏚ÛYÜÝᦔ9Þ᛻u⚪C.ÐᾦḄp⌕ᡂᑖ5âᾦã⏚ᵞÐåæ=ç+dḄÐᾦ[èHéhID.ℍ⃔⏀íµ'ÉCîµ'Éïðñ¡SO?ḄòḄ5■g⃩ôᡂᑖS:ᓄ14ஹõö÷ᜧ᫑ùᵨúᜧḄíûᢙ◫ûᩞ஺ûᩞR'}ÿ┯ḄA.ᢙ◫ឋB.Ὂῖ⇨C.D.ᵯ15ஹᵬ⏚ḄᵯC"xm=Crrao-+H+,ᐸKa=6.25xl0-5,ᵬ⏚("COO'a,#ᑏNaA)%ᵨ'(ᧇḄ■ῖᑺ஺Ẇ.⊤0ᵬ⏚(HA)Ḅᢓ2345℉7Aஹ8925࠷:,H2CO3ḄKai=4.17xl0-7Ji2=4.90xl011aoᙠ<=⏚(ᧇḄ>?@◀BCDNaA᜜@F◤DHᐙᐭCChKL஺MᑡOPQRḄ(ST25C,Uὃ⇋(ᧇ?ᐸXᡂᑖ)()A.H2cChḄᵯHCO3^^2H++CO223B.\CO2ᐙKH4@(ᧇ?c(A)U]c(HA)C.^pH5.():@(ᧇ?/A1=°16D._`7aᐙCO2Ḅ(ᧇ@⏚(ᧇḄᢓ234b

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LHCOOHtgJ^sCOCgJ+HzOCg)Hi=+72.6kJmo¼½II2CO(g)+O2(g)=2CO(g)H2=-566.0kJmo¼½S2III2H2(g)+O2(g)^=s2H2O(g)H3=-483.6kJ»moF1ᑣIVCO2(g)+H2(g)=^HCOOH(g)Ḅ¿!!=kJ,moF'c(2)Â▅Äᧇºᙠ}ÆÇÈÉᓄᑺÊᙠu"CCh(g)H2(g)ᔠᡂHCOOH(g)ḄᑖI$ËÌ:Ío$:CO2(g)+H2(g)+M(s)oMHCOOH(s)ͤ$:জÍo$Ḅ¿!!0(Ï“ு”ᡈ“ঝͤ$Ḅ.ঞᙠÖ×ØÙஹ9Ú%6ḄᵬஹÛIÜÝÞßᘤᑖáᢗᐭäᐰ6ḄHh(g)CCh(g),ᵬßᘤæᢝឤØឤß"Ûßᘤæᢝé»ឤß"êëì"IÜßᘤᑖáᙠtlஹt2íîាðñᑮó⊝"ᑣtlt2(Ï“ீ”ᡈ“=”)஺(3)ᙠ9Ú1LḄឤßÝÞßᘤ"Ö×ᢗᧇn(C(h)=lmol,QC(h(g)Hz(g)0ᧇᔠᡂHCOOH(g),HCOOHঝa=«ঞAஹBஹCö¨C(h(g)Ḅó⊝÷ᓄ᳛(UஹaBஹacᵫᜧᑮḄùú.টTiØÙu"ûḄó⊝üᦪK=(PþLÿᵨᑖᦪ⊤)஺29ஹ(10ᑖ)ᨵᓄᔠᱥHᶭ⊈ᱥḄ஺ᔠᡂHḄ:

11ħ!ÅÆজCH£H,CH=CH"S'CHCHBrCH=CH32ÇÅÆঝCH3cHO+CH3CHO—^^>CH3cH=CHCHO+H2஺©ª}ᑡ¬⚪!(1)CḄᓄeÈÉ(,DḄÊËÈÉ.(2)ঝḄÌÍo(3)FḄÎ᪀Ð{(»(4)ᑏᵫE`GFᡂHḄᓄeyz{!o(5)Ò✏ÔᓄᔠᱥQHḄmᑖÕ᪀[Öᩩ×}H`QᑖØÙ0H2ÚᡂLᑮm[ÛᱥᑣQḄ,Î᪀ᨵÛ(ÝÞᨵßßàáâÞᨵãäḄßßåáæὃ⇋éÎ᪀)ᐸᑖᑁᙠßßàáḄmᑖÕ᪀ḄÎ᪀Ð{(o(6)ᔬᗏîï⏚)[Ûñò⊈ᔾõöḄ÷ᱥ——ᔬᗏîùḄᧇ஺VCH=CHCOOHúᐭ(ᧇᔠᡂᔬᗏîï⏚Ḅᔠᡂûü(D5ᑺý⌱)஺______________.VCHOஹCH3cH20H!ὃ#ᫀ[ஹ⌱ÿ⚪(ᐳᒹ22⚪஺⚪ᙳᨵᔠ⚪Ḅ⌱⚗)1ஹAூ᪆௃A.SO2ᐹᨵឋ!"⁐$ᵫ&SO2'()*+,ᓻ./01ᵨ&3A┯56B.78ᓄ:;(<=Ḅ>)?ḄCO2ஹWO@>AB*+,02,CD(<ᔾ/0ᵨ&<ᔾ☢ᐹBGH6C.IJKḄᓫMấOᵨ&ᑴᐝᵯSḄᩞᧇCGH6D.V⁐⏚ឋXY⏚Zᐹᨵ[Ḅ8ᓄឋ\]^⏣8ᓄ`ᐸbcdefg+3hḄCN+,/0᪷jABklm⁐nᓄopᑨrOᔲt⏀ᦑᵨ&wxyzOᔲ⏀{DGH6ᦑᔠᳮ⌱⚗OA,2ஹD

12ூ
᪆௃A.%ᨵᱥᨵ⏚'(O—ஹ)*(OHஹ+*(COO—,-./012A⌱⚗567B.᪷9%ᨵᱥḄᑖ:;᪀=2>⏣)*@AḄBᨵ4CDឋBF:2Gᑖ:-ᨵH)*(>IJKL@AḄ)*M20⍗FeCbOPQR⁐2B⌱⚗567C.⏣)*ᡠᙠḄC>ᐸWXCC@AYᵬ*;᪀2[\0ᐳ^☢2ᦑ%ᨵᱥᑖ:ᡠᨵBF:[\0ᐳ^☢2C⌱⚗567D.ImolH)*(OH0>ImolNaOHabcd2Imol+*(COO—0>ImolNaOHabefcd2Imol%ᨵᱥᨵImolH)*(OHஹImol+*(COO—M,h!JImol%ᨵᱥ\>2moiNaOHabcd2ᑖ:-ᨵXCIJ,\jk6molHablᡂcd2D⌱⚗┯n72#ᫀ⌱D஺3ஹDூ
᪆௃oᐗqḄᯚ⁐s⁐2tᐗqḄᯚ⁐R⁐2uvwtᐗqḄᯚ⁐x⌕z{|⁐}~ᴻ2joᐗqḄsᐝḄ᡾஺ᯚ⁐cdx2KLvwxᑮᯚᕈs⁐2-ᨵNa+,[0ᑨK+Ḅᙠ>ᔲ2ᦑD56Ḅ஺ᦑ⌱D஺4ஹCூ
᪆௃A.ᵫᱥᓄ2OCN-CY+42NY32ᙠM᩽NḄᓄᔠᓣ2M᩽Y᩽2N᩽Y5᩽2A⚗567B.ᙠᜐᳮ{2M᩽▬¢ᵯfOP5ᵯ₹¥¦2ᡠj▢¨:ᔣM᩽ª«2¬1Y▢¨:ᣚ¬2N᩽cd=YO+4e+2HO=4OH-,N᩽▬¢ᵯ₹¥¦2□¨:ᔣN᩽ª«2¬2Y□¨:ᣚ¬2B⚗56722C.᪷9ᵯ₹°ឤ2ª«Ḅ▢¨:ஹ□¨:ᡠ²ᵯ₹³ᦪ´µ5ᵯ₹³ᦪ2u¨:ᡠ²ᵯ₹[@¶2ᦑª«Ḅ▢ஹ□¨:³ᦪ[@´2C⚗┯n7D.M᩽ab.ᓄcd2e!>cd2bᡂ·H+,D⚗567#ᫀ⌱C஺5ஹCூ
᪆௃Aஹ“e¹º»2ᐸ¼½ᩭ”ÀÁᑮOf2ᦑA[⌱7Bஹ“ᤅÃᦪᓝÅ”ÀÁᑮᤅÆ2ᦑB[⌱7CஹᓣÇᢣᵫÉ᝱ËÌKLÍᡂÎ2ᦻÐᨵÀÁ2ᦑC⌱7Dஹ“ᐸÑÒÓÔ᧼ὅ×ØÙ”ÀÁᑮÚa2ᦑD[⌱7

13ᦑ⌱Co6ஹBூ
᪆௃᪷9ᵯÛcdÜ=\ÝᙠcdCd(Hg)᩽Þ᩽2Cdᜫᵯ:2ab.ᓄcdàbHgÞOᑺ2[!lcd2â᩽HgY5᩽2CcP+ᔣᵯ₹ã¦Ḅᵯ᩽A«ä2A┯nஹB567᪷9³cdÜ=\ᱥBᵯ᩽ḄHg[!lcd2C┯n72a᪷9Ü=\åbᡂ3moiHg,«2moie;ᑣbᡂamolHg«\molḄᵯ:2D┯n7ᦑᔠᳮ⌱⚗B஺7ஹBூ
᪆௃ᵫᵯÛ³cd\2çèᵯÛéᵯxYFᵯÛcd,᩽cd=YMH+OH-e=M+HO,5᩽cd=YNiOOH+e+HO22=Ni(OH)+OH7oêᵯÛᐙᵯxYᵯfÛcd2▢᩽cd=Y22Na++2e-=2Na,□᩽cd=YSx”-2e-=xSᐙᵯx2XCᵯÛḄᵯ᩽L25L52ÉAWhḄNa+(□¨:)ᔣ▢᩽(ᵯÛḄ᩽)«ä29íf#஺ூ
௃A.᪷9jᑖ᪆2>a᩽@AḄoêᵯÛḄ᩽2ᡠja᩽YçðᵯÛḄ᩽2ᦑA┯n7B.ᵯfx□¨:ᔣ▢᩽«ä2ᡠjᐙᵯx2Na-ñ{ÉAWh◌óᔣM᩽«ä2ᦑB567C.çèᵯÛḄ᩽ab.ᓄcd2cd=YMH+OH--e-=M+H2O,ᦑC┯n7D.ᐙᵯx2Nᵯ᩽Y□᩽2cd=YSx"2e-=xS,᪷9ᵯ:°ឤ2᜜ᵯåñ{2moiᵯ:2N᩽bᡂxmolSᓫ2ᦑD┯n஺ᦑ⌱B஺8ஹAூ
᪆௃A.n(öᔠÎᱏ“5.6^=0.25mol,CH4>C2Òᙳ-4CH,ᑣöᔠÎ-ᨵḄçF:ᦪùY0.25molx4x6.02xl023=6.02xl023,ᦑA567B.CO(g)+HO(g)^CO(g)+H(g)AH=-41kJ/mol,cdḄAH>!lcdḄᱥḄúûᐵ2>Ü=ᱥýḄᓄ222þÿᦪᨵᐵᦑB┯C.2NaCl(s)=2Na(s)+CL(g)ḄAS>0,ḄᑖᦑḄAH>0,ᦑC┯D.ᐭA1H2Ḅ⏚ឋᡈ"#ឋ#ឋ$Mg?+%&'᪷)*ᜧᐳ-⏚ឋ$NO3-ᙠ⏚ឋᩩ1ᐹᨵ"'ᓄឋ%456ᡂ&8%⚪:;ᦑD┯

14=ᫀ⌱A஺ூBC௃E⚪Ḅ᧕┯BD,⌕H:I⏚ᐹᨵ"'ᓄឋ%JKLM&8஺9ஹDூ
᪆௃^Otr00"C.ImolOPQ%3m0IH26ᡂImolRRSTUImolHz6ᡂVWX%6ᡂᑣ1molZ[\]⏚%^_86ᨬabὑ4m0IH2,C┯D.ᑖ*$dᨵ1e⛳URg*hiRg*jᨵ2eklḄHg*mnᑖ*$oᨵpឋRg*Dqr஺=ᫀ⌱D஺10ஹCூ
᪆௃A,᪷s⚪:ᵯuvwLxyᩖḄ{ῖ⇨“”6ᵯᵯw$bὑCU2O,ᵫnvᐭ8Cuῖ⇨6ᡂCsO,ᵫᵯCu᩽ᵯ᩽Cu2O+2e-+H2O=2Cu+2OH-,C112OgᡂCu,᦮ew$Cukᓄᑺ'ᓄᑺ02,A⚗qrB,ᵯq᩽Ḅᵯ᩽Cu2O+2e-+H2O=2Cu+2OH-,B⚗qrC,ᵯ᩽ᵯ᩽Li-e=Li+,ᵯ$vwO.lmolᵯ*6ᡂ0.1molLi+,Li+wᵯᔣCu᩽,$bὑ஺2ᱥḄᝍ£=0.025mol,ᙠ᪗¥¦§O2Ḅ¨
.025molx22.4L/mol=0.56L,C⚗┯D,4ᵯw$bὑCU2O,ᵫnvᐭ8Cuῖ⇨6ᡂCU2O,D⚗qr=ᫀ⌱C஺11ஹDூ
᪆௃A.CaO©ᨵ"gឋᦑ■«¬Ḅ'ᓄ®d¯ᑮ■±Ḅ²ᵨA⚗┯B.ấiµ¶·ᱏḄ¹⌕ᡂᑖiấᓫB⚗┯C.Feᐹᨵgឋ»Pb2+ஹCu2\Cd2\Hg2+¼½JK)*gᡠ¿ÀÁÂÿÄᦔᙢÇ◀ÉÊË$ḄPb2\Cu2\Cd2\Hg2+¼½JK)*iᑭᵨFeḄgឋ%ᔾ▬ឋÏᐵC⚗┯D.SO2%ᨵ⁐ᱥᓄᔠ6ᡂÏ⁐ᱥᵨÒÓÔÕஹÖஹ×ஹ₝ÙÚ¼D⚗qr=ᫀ⌱D஺

1512ஹBூ᪆௃A.Üᧇᵯuv'8Ḅ᩽q᩽ᑣbᵯ᩽q᩽6gᵯ᩽4lT+O2+4e-=2H2O,ᦑAqrB.ᵯ$ᨵ4moiᵯ*6Þbὑ'8ḄᱥḄᵯᔳ=lmol,᪗¥¦§¨22.4L,ᑣᜧàbὑ᪗¥¦4§822.4LX5=112L,ᦑB┯C.á⏚âgã¿äᨵåᱥ'ᓄᡂæ'ᓄRVá'ᓄã¿äá&᪷)*'ᓄᡂá⏚᪷)*ᑣçxèã-ᙠé5êP»ᨵåᱥ'ᓄᡂCO2ᵯ*ᦑcqrD.᩽ëHSᙠá'ᓄã²ᵨÞᓄSO42-,ᜫᵯ*6'ᓄᵯ᩽iHS*4H2O-8e-=S(V-+9H*,ᦑDqrᦑ=ᫀB஺ூBC௃ὃîgᵯuï²gᳮ¿ñᵨòH:òḄóᵨi⚪ḄᐵT஺13>Dூ᪆௃A.ᯚ⁐iᱥᳮ®ᓄᦑA┯B.õ'ᓄᱥḄᜧ᣸5¶÷ᐝᓄùúûஹ⏚üP᛻þ⚪ÿᦔ
CO2⌼ᡂḄᦑB┯C.ḄᾦᓄᦑC┯D.ℍ⃔⏀!C"#$!SO2ᐹᨵ'(ឋ*+,-./SO2Ḅ0Ḅ■2⃩4ᡂᑖᓄᦑD67஺9:ᡠ<=ᫀ?D஺14ஹCூB᪆௃A.EFḄG/HIJG/KᜧMNKOPJḄQឋRE⌕TEᩞḄᢙ◫ឋXYᦑA67B.ZEᩞᦋ\]^Ḅ_ᡂ`a᪀cJḄᢙὊ⇨ឋ⌕YᦑB67C.᪷gJḄG/?h2%-4.3%,EḄG/?h0.()3%--2%,ijG/hJ>EᦑC┯D.Eᩞ`Jlᔠ]lᨵ]^lnᵯnpᦑD67⚪0⌕r⌱┯Ḅᦑ⌱C஺15ஹCூB᪆௃A.H2cCht⏚ᑖvᵯwᵯwxyz?H2cO3=H++HCO,ᦑA┯B.{OCO2ᐙ}~Ḅ⏚ឋFc(A)ᦑB┯;

16c(HA)c("+)IO஺C.pH?5.0ᧇF.~-\=_L=—5=0.16,ᦑC67c(A)K,,6.25x1O-5D.ᵫ⚪Fijᵬ⏚(HA)Ḅᢓ℉OIA)ᐙCO2ḄᧇFHAḄNRᜧᡠcIᐙC(hḄᧇG⏚ᧇḄᢓROᦑD┯ᦑ⌱C஺16ஹBூ
᪆௃A.NஹPᐗ!ᱥ◤⌕Ḅ¢/ᐗ!£¤¥FNஹPᐗ!Ḅ/RO¤F¦§ᱥ¨©ªn«¬®¯°A67B.“²⁐´µ”$·¸yF?\¹´µ©ªºᑴ¼½¾¿⌕〉¹ᵨÂ`ÃᧇB┯C.Ci?+Å]^wÆǹ¼ஹ¼ÈḄÉÊឋËÌÍÎFᢥ᪗Ñ-ᐭÓÔiÕÈᩔC67D.ᑴ×ᵨØÙ¹ᵨḄÚÛÜᵫÛÜ*¸-ÚÝ
¬ḄÞßᔠᡂOᑖÆᩞᧇD67ᦑᔠᳮ⌱⚗B஺17ஹAூ
᪆௃A.ᵫ30âᐗ!Zn,ãäåæ83âᐗ!BiçèḄéJa^I᪶ë^IᓄìᓄᦑA┯B.⚪FíîḄï$ᐗ!JaஹZnஹBil]^ᐗ!ᦑB67C.+JaḄÆᦪ?H3,FÆᦪ=278-113=165,FÆᦪñÆᦪT?165-H3=52,ᦑC67D.+JaòIóôᕜöóIHA÷øù÷øᐗ!F(ÆúûᨬᜧḄᦑD67=ᫀ⌱A஺ூ௃ᓄìᓄḄýþḄᓄìÿḄ
ḄᓄḄᡂ᪶ᑁḄᓄ஺18ஹDூ
᪆௃ᵫ
ᓄᔾᦈakJᡂImol᝱!"bkJ,Imol᝱#ᓄ"$᝱!%"ckJoூ
௃A.
0.5molN2(g)1.5molH2(g)&ᡠᨵḄᓄᔾᦈakJᦑA┯+,B.NH(g)-NH(1)H=-ckJ«mol1,ᦑB┯+,33C.ᵫN(g)+3H2(g)62NH3(g)AH=2(a-b)kJ»molᦑC┯+,2

17D.ᵫN(g)+3H(g)W2NH3(1)AH=2(a-b-c)kJ.mol1,."⌮012Ḅᦪ456ஹ785220ᑣ2NH3(I)@2(g)+3H2(g)AH=2(b+c-a)kJ»mol-1,ᦑD:;,ᦑ⌱=D஺19ஹAூ
᪆௃᪷?R,W6@ABCDᦪR"WḄEFR"OᐗHW"SᐗH,᪷?a+b=g(d+e)XYḄDᦪ"12,IJ"XY6@AᡠKXYELMHᐗHELMNaᐗH,ὃ⇋ᑮ2Q=C-d,ᡠ2KX"HᐗHY"NaᐗHSTZ"A1ᐗH஺ூ
௃A.W,Z,Y,RᑖVW1S,Al,Na,OXYᐗHᡠKFZ[D"=r(Y)>r(Z)>r(W)>r(R),A⚗┯+,B.X]YᡂḄᓄᔠᱥᓽNaH,H"-1aHᐹᨵ1LᵯdNa":EaNa+ᐹᨵeLᵯdᡠKB⚗:;,C.WḄᨬgaᓫ᪶▢jᓽS%RḄᓽO”kឋS%mnᡠKᜫᵯpqmnC⚗:;,D.ZḄᨬrasᓄᱥW1tᓄᱥ"A1(OH)3,YḄ"NaOH,QὅK01D⚗:;,vᫀ⌱A஺ூ௃xyFZᜧ{ᐜxyᕜ~ᦪᕜ~ᦪᜧᵯdᦪFZᜧ,ᕜ~ᦪ56xyDᦪDᦪᜧFZ{஺20ஹAூ
᪆௃A.☘HᵫCஹHஹOYᐗHᡂ᪀ᩖᨵᱥA7ᔠ⚪,B.ᐰ▢jᵫNஹHஹOஹC1XYᐗHᡂᐗHᨵᱥBᔠ⚪,C.ᔠEYᐗHᐗHᨵᱥCᔠ⚪,D.ᓄᵫồeYᐗHᡂᐗHᨵᱥDᔠ⚪஺ᦑ⌱A.21ஹAூ
᪆௃A⌱⚗¡ₐ&Mᔲᨵ¤¥ᱥ¦ᔣₐt&¨©FeCbª$«⁐ᑣᨵᑖ¥ᱥ¦ᦑA:;7ᔠ⚪;B⌱⚗pᵨpH¯°±²84³´$ḄpH,J"84³´$ᨵµ¶ឋᦑB┯+7ᔠ⚪,C⌱⚗◀¸¹&ºᨵḄ»¹¤¨©¼t¹¤½t01¾ᡂ2,4,6—¿¹¤]¹.ªpᵨÀÁஹᑖ$

18ᦑC┯+7ᔠ⚪,D⌱⚗ÂÃᑴᜓÆ⏚ÆÈᔣ¯É&ÊË©ᐭÆ⏣ஹÎÏ⏚ஹÆ⏚ÐÑᱏ©ᦑD┯+7ᔠ⚪஺ÓÔᡠÕvᫀ"A஺ூ×Ø௃¤ÚÛ@⌕ᵨÝj஺22ஹCூÞ᪆௃ᔣE²ḄÏ⏚═
MnSO஺ª$&¨ᐭ〉â⏚ãª$ª$ᕈ«å⁐æç+éBiCh-sᓄ"MnOr¨ᐭÀstª$«å⁐³ᜫê¾ëæçMnOjìH2O2sᓄ"02ᨬí¨ᐭ〉KIîïª$ª$ð᠒ᡂò⁐æçH2O2ìKIsᓄ"L;ூóÞ௃A.sᓄᑺḄsᓄឋᜧsᓄêᱥMi?+éBiOysᓄ"MnO/,BiCh-ḄsᓄឋnMnOj,ᦑA:;,B.¨ᐭÀstª$«å⁐³ᜫê¾ëæçMnOjìH2O2sᓄ"02,ᦑB:;,C.┱⏚ãᐹᨵnsᓄឋᔣö⏚ãª$&¨©KIª$rpésᓄ"IO”ᡠKª$E²ò⁐ᦑC┯+,D.ᵫঞ&øù=Ớjéstsᓄᡂᓫ¦ỚᦑD:;,ᦑ⌱C஺ூ×Ø௃û⚪ὃü¾sᓄk01&sᓄឋnýḄᑨ
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rᓄᑺᓄḄᱥhoஹ⌱⚪ᐳ84ᑖூ
᪆௃AḄᑖ!"C2H4,A"#$
ᓽ&᪀(!"CH2=CH2,᪷*+⚪
1,D,-./012
3Dᑖ45ᨵ78
ᓽD49ᨵOH,D/:✏<ᓄᔠᱥ
ᓽD49ᨵ>?
DḄ@AᑖBC"D16/13.1%=122,᪷*>

19#FGHDḄ&᪀(!"ீOுCH2CH2OH,᪷*LFḄ&᪀(!
GHCḄ&᪀(!"HOCH2cH2OH,᪷*MN
GHBḄ&᪀(!"CH3OH,*Oᑖ᪆Qூ
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ᓽ&᪀(!"CH2=CH2,᪷*+⚪(1),D,-./012
3Dᑖ45ᨵ78
ᓽD49ᨵOH,D/:✏<ᓄᔠᱥ
ᓽD49ᨵ>?
DḄ@AᑖBC"D16/13.1%=122,᪷*>#FḄ&᪀(!GHDḄ&᪀(!"cH0H,᪷*LFḄ&᪀(!
GHCḄ&᪀(!"2HOCH2CH2OH,᪷*MN
GHBḄ&᪀(!"CH3OH,(1)᪷*RSᑖ᪆
BḄ&᪀(!"CH3OH,ᓽᑖ!"CHQ;D,-./012
3Dᑖ45ᨵ78,ᓽD49ᨵOH,D/:✏<ᓄᔠᱥ
ᓽD49ᨵ>?
DḄ@AᑖBC"D16/13.1%=122,᪷*>#FḄ&᪀(!
GHDḄ&᪀(!"(2)CḄ&᪀(!"HOCH2cH2OH,9ᨵḄT,UVWQ᪷*ᔠᡂYZ
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24(2)12[Ḅ12NaS+SO2+H2O=H2S+NaSO3,SO+2HS=3SI+2HO,ᦑᱥbS22222(3)ᑴ12Ḅsᡈ⏚ḄFG>s]ᑴSO2ᡂ>᳛(4)⏚⍗⏚᧕ᑖ&ᐭḄSChᑣ-.⏚ឋ⏚ᑖ&(5)/c4bᔲᙠNa2sOḄtbYc-¡¢£¤⏚,☟,§¨-.(ᡈª,ª.)FGBaCh-.¬MNᑣTU5ᨵNa2sChᩖ¯஺II.(6)D0জḄ°bᔠ3-.ᐜ±ᡂ²³⁐30s3-.´µ±S⁐123Ḅᔠ.¶Gᐭ*ᓄ,-.c·⁐MNᑣᨵFe2+ᡂ]ᑨ¹Fe3.ºS2O3”\Fe»ᔠ3-.ᐜ±ᡂ²³⁐30s3-.´µ±S⁐TUFe,+3S2O32-0Fe(S2O3)33-12>᳛VFe#S2O3”¼½Ḅᓄ\12¾¿À@⊝⌮ᔣÃÄᐜ±ᡂ²³⁐3±S⁐TUᡂ²⁐ÅᔠᱥḄ12>᳛Æᓄ\12>᳛᠒È᜜Fe?ÉS2CV-ᓄ\12Ḅ{sᜧ,ËÌFe3++3s2032-OFe(S203)3h(²³⁐)@⊝⌮ÃᨬÎ-.´µS⁐ÏÐsᓄឋAgDFe*ÑD0ঝf[Ag*ÉS2O3”¼½Ḅᓄ\12ᔠD0°ᐜᡂI⁐KLMN,O₩3MN-&QᑮS⁐-.TUAg+ÉS2CV-ᡂÒÓḄÅᔠᱥsÔWAg+ḄᓄឋS2(V-Ḅ\ឋXÕ(8)Ag2s2஺34Sᐗ`ᓄᔠa+2aᡂḄAg2s4Sᐗ`ᓄᔠa-2ab\cᱥᑣfgcᱥ2bᓄcᱥ᝞×cᱥbH2s03,^ºAg,ØÙᓄᑣᓄcᱥ2H2s04,ᔠijឤ]gÈÚ12ᱥ2H2஺[12ḄᓄÛt{|Ag2s2O3+H2O=Ag2S+H2s04(9)ᔠD0জஹঝஹঞ]gNa2s2O3ÉÜÝ□ri[ᓄ\12ÜÝ□riḄᓄឋÞÕஹrisᜧßஹ12ᱥḄᵨᨵᐵ஺27ஹ2KMnO+16HC1=2KCl+2MnCh+5ChT+8HOᡈKC1O+6HC1=KC1+3ChT+3HO2SCL+2H2஺==SJ.+4232SOiT+4HCIᑴᑖ.âᧅḄäåæ¤⏚ᒴ>FèéᐭᰚëḄètæìÉᐙᑖîïஹ12XYðìñᡂSCI2◀óSC12ôᨵᔾᦈC12ஹSC12Ḅூ
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