2023年上海市北虹、上理工附中高考数学倒计时模拟卷含解析

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2023
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௃3x,x>1(1)Ra=2S/(x)=|2x+l|+|x-l|=1(2)Ra>0S/(X)=|OX+1|+|A:-1|<(6?-l)x+2,--1/(D=4+1>1.ᡠ/(X)>1ឤᡂ".R4=0S/(x)=|x-l|+l>l,\/প=1,஻_>1ឤᡂ"`ᔠ⚪&.Ra<0S=+/(-b)=c+b,b—2Wa<0,ᑣᦑ/(_>1ឤᡂ"`ᔠ⚪&fba<-2,gk,ZீIᦑ/(_>1ឤᡂ"`ᔠ⚪&.jkae(0,+oo).ூ௃N⚪l⌕ὃnEḄ$%ὃ᪷pnEឤᡂ"BqᦪḄOQὃᑖrstḄᦪ(-.u%34W᫏⚪.21.(1)-4(2)713ூ
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17cc(1)᪷pwxyz{x<|Uᓄ{kᐵ~Btank,ᵫyz{xᓽTB$;22(2)ᙠAACDW᪷p☢xBCO᪷pᳮBA0ᵫᳮBsinNADC,ᓽTBt.ூ$௃(1)V5sin(A+B)=4sin2,26sincos=4sin2,,.<£<£,,sin£>0,.-.tan£=^022222,2c1-tanVcosC=cos2--sin2-222I2C71+tun—2(2)ᙠAACDWᵫ(1)^sinC=—7Lo=gx7xC£)xr=6s஺஺=3,7ᵫᳮCAD-=Z?2+CD2-2Z?-CDcosC=49+9-2x7x3x1=52,7AD=2ᙠAACDW74GADAC..V7_2,,..sin/AZ)C=-=sinCsinZADC2V1313sinZADB=sinZADC=vw13ூ௃⚪ὃJ{ឤᣚBஹ☢xஹᳮஹᳮ$J{?ὃ0B$1234W᫏⚪.22.(1)ᓫ(-2,-34x),ᓫ(ߟ34ஹ+8)b(2)$᪆f(3)(-8,2).ூ]᪆௃⚪ᑖ᪆(1)Eᦪ/(x)BᑭᵨᦪᓫឋḄᐵ~TBCᦪ/(x)Ḅᓫ.(2)᪀⌼ᦪh(x)=f(x)-g(x),ᑭᵨᦪBCᦪM¡ᙠ(-1,¢)k⌴\஻(-1)=0,ᑣ/?(2¥0,ᦑ¦ᡂ".(3)

18|(2)᪀⌼#ᦪ஻(x)=/(x)-g(x),ᦇᑖᡂ52,=2,©2#ᦪ/z(x)Ḅᓫ/ឋஹ᩽ᨬᵫ!Ḅ.⚪]᪆b9পr(x)=R—2(x+l)4*1E—2(X?+3x+1)(x>-2)*x+2(x)<஺/+3+1>0.]xு—3+£2(x)>()]—2(2)BMx)=஻x)-g(x)=21n(x+2)-(x+1)-Z(x+l)(x>-1),ᦇ=2ᵫ⚪£(-1,))(%)ீ஺ឤᡂ.-2(ᔆ+3x4-1j"(X)x+2-2(x+3)(x+1)x+2••%>-1,஻'(%)ீ஺ឤᡂ,)পᓫ/⌴+.¢-1)=0,••xe(-l,+oo),-1)=0ឤᡂᓽ“X)-g(x)<0.£஻x)vg(x)ឤᡂ.

19(3)§஻(x)=_2(+1)_᝕2x2+(k+6)x+2k+2~x+2'ᵫ(2)URᦇ=2S/(x)2SE4x+lுO,AS2(x+l)/i(-l)=O,ᓽ/(x)-g(x)>0ឤᡂ".jkAḄOQ(—8,2).⚪l⌕ὃᦪᓫᦪḄ¸¹ᦪឤᡂ"#⚪ḄB$u%.ºV#BᦪḄᓫ,»¼ᦪ#⚪Ḅ½⚪¾¿¼½ÀᐜBÂÃᯠB⌕Å&Æᑖ§ᑖ$.yஹJÇ#Vȼឤᡂ"#⚪Vȼ«ᙠឋ#⚪⌕Å&O¼ᨬᜧɼᨬN.