四川省乐至2021-2022学年十校联考最后数学试题含解析及点睛

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15ூ௃_5xl+6x2+7x4+8x2+9xl(1)ᵬḄᙳᡂ+=7(-),,-1+2+4+2+1•••12Ḅᡂ+34ᑮᜧ78᣸ᑡ;<3ஹ4ஹ6ஹ7ஹ7ஹ8ஹ8ஹ8ஹ9>10,12ᡂ+Ḅᦪb=——=7.5(-)
2ᐸC=\x[(3-7)2+(4-7)2+(6-7)2+2x(7-7)2+3x(8-7)2+(9-7)2+(10-7)2]=—x(16+9+1+3+4+9)10(2)3ᙳᡂ+>ᵬஹ?@Ḅᡂ+ABᙳ;7-C3ᦪ>ᵬ17-DEḄFᦪ4GC3ᦪ>ᵬ17-ḄFᦪᨬIJ18-ḄFᦪᨬIC3>ᵬḄᡂ+KḄᡂ+LMᔠDEᔜOPCQ⌱STUVᕒXYKZḄ[C⌱\XZCO;]^_ᑖḄ`aᜧ.ூ"c௃e⚪ὃhḄiᩩklmஹᙳᦪஹᦪஹᦪḄMᔠnᵨ.opqrᙳᦪḄCᳮtḄᭆvC`w᪷Ḅᦪ#$Mᔠᑖ᪆.22ஹ(1)A(-4,0),B(3,0)(2)--(3)46ூt᪆௃(1)xy=0,yxḄzCᓽyA,BḄᙶ᪗27(2)}MD±x~CᵫCO஻MD^OD=3,x=-3ᐭt᪆^M"ᙶ᪗C^ONḄC᪷SBMC=—,A4yaḄzMN(3)M"}ME஻AB,xNO=m,——=k,Dᵨm,k⊤CO,EO,MD,ME,yM"ᙶ᪗CᐭNB^k,m,aḄᐵCᵫCO=2km+m=-12a,^Ct^k,ᓽy.ூt௃(1)xy=0,j?||0=ax2+ax-12a(a<0),.".xi=-4,X2=3,...A(-4,0),B(3,0)(2)᝞m1,}MDJ_x~,

16r1•MDJLx~,OC_Lx~,.MD஻OC,MBOB——=——aNB=MN,MNOD.OB=OD=3,AD(-3,0),.,.x=-3Cy=-6a,M(-3>-6a),/.MD=-6a,VON/7MD.ONOB1.♦.ON=-3a,᪷⚪^

17:.NEMBNABMvNCMB=2NABM,ZCME=ZNME,vME=ME,ZCEM=ZNEM=90°,AACME^AMNE,ACE=EN,kMN,ஹwNO=m,------=k(k>0),NBVME/7AB,ENMNME_0N~NB~OB~/.ME=3k,EN=km=CE,:.EO=km+m,CO=CE+EN+ON=2km+m=-12a,,rtn-12ᓽT=a2k+\AM(-3k,km+m),km+m=a(9k2-3k-12),(k+1)x—=(k+1)(9k-12),a.-12=9k-12,2k+\:.k=—,6.MN_5"W"6ூ()௃x⚪ὃ,Ḅey(kᦪ>᪆zḄ{
|kᦪḄrs}ឋ4
|kᦪ~>᪆PleyḄᔠᵨ
.ᜧ.23ஹ(1)X]=2+V7,x,=2—V7(2)X]=1,w=<3.ூ>᪆௃(1)ᑭᵨz{>;(2)ᑭᵨUzᑖ>{>.ூp>௃(1)>&஺=1,b=Y,c=-3,4ac-(—4)2—4xlx(—3)=28>0,.—b±yjb2—4ac—(-4)+>/284+2^72+#j2a2x12

18*,•᳝=2+>/7,&=2-y/y(2)t<ᓄ;<(X—1)2—2(X+1)(X—1)=0,Oᑖt^<(x—l)[(x—1)-2(x+l)]=0,᦮ᳮ^<(1)(*3)=0,.♦.X—1=0ᡈ—X—3=0,%=1,%2=-3.ூ"c௃e⚪⌕ὃhtTᐗ?FḄ`CopqrtTᐗ?FḄ¡¢£ᵨ¤<¥¤ஹOᑖt¤ஹ¤ஹ¦¤CᔠḄᱯ"⌱\ᔠ〉ஹ¨©Ḅ¤it⚪Ḅᐵª.13a24,(1)j=-x2+x--(2)j=-x+1(3)x=-2Cᨬᜧz;T<(4)«ᙠC"஺Ḅ®ᙶ᪗;-3ᡈ¯ᡈ224-.ூt᪆௃(1)x?F°ᦪḄ⊤±;

196=-5m+n\m=-À"4ஹ஺Ḅᙶ᪗ᐭTF°ᦪ⊤±

20Cj3ஹw(஺ᙶ᪗%1
(஺Ḅᙶ᪗%]
஻,74(Ḅᙶ᪗%0,2),(஺஺Ḅ(,2m=-tᑣ:<13ᓽ:12112n=—rn+-r+t———/d—,22222,2(஺ᙶ᪗ᐭজz¡>&¢=±J7.ᦑ(஺Ḅ£ᙶ᪗%&-3ᡈᡈ-.ூ()௃x⚪ὃ,Ḅ|kᦪᔠ¤ᵨ
¥¦ᑮr2¨©ஹ¨ªq2Ḅឋ49
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x⚪.ᜧ.25ஹx+2ூ>᪆௃ᐜ¬®¯Ḅᑖz°ᑖ
ᓄ²
³´µ◀{.ூp>௃x+1x+2x-2
>&·z=-----x-----------------=x+2x-2x+1ூ()௃G⚪¹(ὃº»¼8ᑖzḄᓄ²Ḅᵨ
56°ᑖ}½ᑖ>⚪ḄᐵA.26ஹ1
¾>᪆2
CD=2x/^+3;3
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2¿ூ᪆௃C⚪ᑖ᪆&À©ᵨ&1
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Â⌕ÄÅNDAB=NCAE,ᓽ᪷gSAS>ÆÇ⚪2
ÈÉ&CD=V^AD+BD.ᵫ4DAB^^EAC,eBD=CE,ᙠRtAADHDH=AD«cos30°=—AD,ᵫAD=AE,2AH±DE,ÊoDH=HE,ᵫCD=DE+EC=2DH+BD=6AD+BD,ᓽ>ÆÇ⚪ËÌÍÎ&3
᝞r3
ÏBHLAE:H,`aBE.ᵫBC=BE=BD=BA,FE=FC,ÊoAஹDஹEஹCq(ᐳᙊ,ÊoNADC=NAEC=120஺
ÊoNFEC=60஺
ÊoEFC91/2HF4
ᵫAE=4,EC=EF=1,ÊoAH=HE=2,FH=3,ᙠR3BHF
ᵫNBFH=30஺
——=cos30°,ᵫGᓽBF>ÆÇ⚪.

21ó⚪t᪆<ôåõᵨ<1
ö÷<᝞m2,":ZBAC=ZDAE=120°,/.ZDAB=ZCAE,ᙠADAEAEACCDA=EA,NDAB=NEAC,AB=AC,.,.øDAB^AEAC,(2)ù

22Vq2ABCDd2
NABC=120஺,/.ABD,ABDC91/2

BA=BD=BC,,:EஹCᐵ:BM8Ò,.♦.BC=BE=BD=BA,FE=FC,:.AஹDஹEஹCq(ᐳᙊ
:.ZADC=ZAEC=120°,:.ZFEC=60°,.,.EFC91/2
(4)VAE=4,EC=EF=1,.".AH=HE=2,FH=3,ᙠRtABHF
VZBFH=30°,HF..-----=cos30°,BF•BF=^=2^.227ஹ(1)p¾>᪆(1)6-273ூ᪆௃(1)`aOEbDF:(H,ᵫᑗVḄឋ4oNF+NEHb=90஺
ᵫFDLOCoNOOH+N஺”஺=90஺
Õg8⚔/Ḅ×nof=NOHO,NF=NOO",ÕgNCBE=ØNOO”
ᓽÄ2(1)Õgᙊᕜ/×ᳮ¦ᐸÊÉoNF=NCOE=1NC8E=30஺
oODḄÜ
ᑭᵨ┦/1/kᦪḄ×noOHḄÜ
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ᑭᵨ┦/1/kᦪḄ×nÞ<ßEFḄÜ.

23ூ௃(1)OE஺”••£஺஺Ḅᑗ0£஺஺ḄC.OELEF..*.ZF+ZEHF=90°.VFD±OC,:NDOH+NDHO=90஺.■:NEHF=NDHO,
.ZF=ZDOH.■:ZCBE=-/DOH,21:./CBE=-/F2(1)VZCBE=15°,:.NF=ZCOE=1NCBE=30°.•஺0Ḅ2g,DOC,:.OD=BᙠRtAODHcosNDOH=OH
.OH=1.:.HE=20-2.EHᙠRtAFEH
tanZF=----EFEF=gEH=6-2ூ௃⚪⌕ὃ#ᑗḄឋ%&'()(*Ḅឋ%ஹᙊᕜ(.ᳮ&)(0ᦪḄ2ᵨ45ᙊᕜ(.ᳮ6ᑗḄឋ%⚪Ḅᐵ8.

24