C语言程序设计配套习题-带答案.doc

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1、《C语言程序设计》配套习题集答案2010-5-10目录概述2类型、运算符与表达式19分支结构21循环结构26函数36数组46C预处理器59指针60结构65位运算76文件77概述一、单项选择题。12345678910DBAACDBABB11121314151617181920A此题删除CABCCCCC21A二、程序设计题。1.#includeintmain(){printf("%d",EOF);return0;}2.#includeintmain(){inta,b;/*变量的声明*/scanf("%d%d",&a,&b);/*输入两

2、个整数*//*求两个整数的和,乘积,差和商,并且输出*/printf("%d%d%d%d",a+b,a*b,a-b,a/b);return0;}3.#include#includeintmain(){doublex1,y1,x2,y2;doublea,b,c;scanf("%lf%lf%lf%lf",&x1,&y1,&x2,&y2);a=(x1-x2)*(x1-x2);b=(y1-y2)*(y1-y2);c=sqrt(a+b);printf("%.2lf",c);return0;}1./*countblanks,tabs,and

3、newlines*/#includeintmain(){intc,nb=0,nt=0,nl=0;while((c=getchar())!=EOF){if(c=='')++nb;if(c=='t')++nt;if(c=='')++nl;}printf("%d%d%d",nb,nt,nl);return0;}2.#include#includeintmain(){inti=1;while(!(i%3==1&&i%5==3&&i%7==5&&i%9==7))i++;printf("%d",i);return0;

4、}1.#include#includeintmain(){inti;doublesum=0;for(i=2;i<=10;i++)sum=sum+sqrt(i);printf("%.10f",sum);return0;}2.#includeintmain(){floats=100,h=100;inti;h=s/2;for(i=2;i<=10;i++){s=s+2*h;h=h/2;}printf("%.2f",s);return0;}3.#include#includeintmai

5、n(){floats=1,t=1,i=3;while(fabs(1/t)>=1e-6){t=-t*(i-1)*i;s=s+1/t;i+=2;}printf("%f",s);return0;}1.#include#includeintmain(){doublet=1,sum=1,pi=0;inti=1,k=1;while(fabs(t)>=1e-6){i=i+2;t=1.0/i;k=-k;sum=sum+k*t;}pi=4*sum;printf("%f",pi);return0;}2.#include#inclu

6、deintmain(){doublex=27;intn=2;while(!(pow(27,1.0/(2*n))<1.00001&&pow(27,1.0/(2*(n-1)))>1.00001))n++;printf("%d",n);return0;}3.#include#includeintmain(){floaty=1.05;intn=1;while(!(pow(1.05,n)<1e6&&pow(1.05,n+1)>1e6))n++;printf("%d,%.3f",n,pow(1.05,n));return0;

7、}1.#include#includeintmain(){doubles=0,a=81;inti;for(i=1;i<=30;i++){s=s+a;a=sqrt(a);}printf("%.3f",s);return0;}2.#includeintmain(){inta,b,i;intasum,bsum;for(a=6;a<=5000;a++){asum=0;for(i=1;i