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时间:2019-08-27
《无机分析化学答案》由会员上传分享,免费在线阅读,更多相关内容在工程资料-天天文库。
1、第二章定量分析概论(答案)1・有关反应和滴定反应MnO+2Na2O2+H2O=MnO42+2OH4-4Na+3MnO42+4H+=2MnO4+MnO2I+2H2OMnO2+2Fe2++4H+=2Fe3+Mn2++2H2OMnO4+5Fe2++8H+=Mn2++5Fe3++4H2OCr2O3+6Fe2++14H+=2Cr3++6Fe3++17H2O解:3MnO2〜3MnO4厶〜MnO?〜2Fe"MnOf〜5Fe2+3MnO_B/2]X[o.1000x10.00-5x0.01000x0.24]x70.942.000x1000=0.0313MnO%=3.13
2、%JCr2O3—2CrO42-CrO72-6Fe2+(JCl*O_[1/6]x[O.1OOOx5O.OO-5xO.O1Ox1O.4O-5xO.588O]x152.O_00]44232.000x1000*Cr2O3%=1.44%2•解:n(Fe)=5n(MnO4・)C(MnO4尸X1000=0.2000(moI/L)5X55.oDn{H[C2O4]2}-5n(MnO4)/4C(H3[C2O4]2=5X0.40X0.2000/4=0.10(moI/L)n(OH)/3=n(H3[C2O4]2)K(NaOH尸{[0」X10.00]/0.1}X3=30.00(m
3、l)(5Fe2++MnO4+8H=5Fe3++Mn2++4H2O5H3(C2O4F2+4MnO4+17H=4Mnc++20C02f+16H20)3.解:Na战。7•10出0〜2HCI〜2N&0Hfl(Na2B4O7・101120)=rinci余)/2Va/Vb=Cb/Ca=l/l.0352lHNa2B107・10H20/MNa2B107・10H20=VaCa-VbCa/l.0352X0.5000/381.4=[30.00XCa-5.50XCa/l.035]/1000Ca=[2X0.5/0.3814]/[30.00-5.50/1.035]=2.622/2
4、4.69=0.1062[mol/L]Cb二Ca/1.035二0.1026[mol/L]3.解Sb2S3+302=Sb203+3S02S02+2Fe3++2H2O=2Fe2++SO42+4H+6Fe2++Cr2O72+14H+=2Cr3++6Fe3++7H2O2Sb-Sb2S3-3SO2-6Fe3+〜Cr2O72'3Sb2S3=CK2CrO7XVK2CrO7XMsb2S3/m样=0.02000X25.20X0.33968/0.3000=0.57073Sb=2XCK2CrO7xVK2CrO7XArsb/m样=2X0.02000X25.20X121.8/[0
5、.3000X1000]=0.40924.解:Mn02+C2042'+4H+=Mn2++2C02+2H202Mn04_+5C2042■+16H=2Mn2++10C02+8H20Mn02〜GO广;5C2O42_〜2MnO°fmNa26。45CrMn0.VrMn0xMMnO2砂0尸皿/阿242丿加样/f)55A一x0.01964x16.50x10」x86.94二(1342丿0.3000=0.8465or84.65%6.解:Ca[C103]2〜12Fe^〜2Cr2O72-丁9QAQQx[o.l000x26.000.02000x6xl0.001x*3Ca[CI
6、O]2二1210000.2000=0.1207or12.07%第三章误差及数据处理1•⑴乂=fXi/n二[20.48+20.55+20.58+20.60+20.53+20.50]/6=20.546矜[1/6吃xz-Xi=0.037/=1dr=[d/X]xl00%=0.18%S=J工[Xi_x]2/w_i]=0.046%⑵AX-u=20・54-20.46二0・08&=[X-P]/P=[20.54-20.46]/20.46二一0.39%2.[1]ni=X1+X2+X3+X437.45+37.20+37.30+37.254Er=土也=37.30-37.35
7、xl0Q%=_°」3%Xr37.35叽环2ni=x-x_0」5+0」0+0・00+0.05_4=0.075(%)応令需W0%"20%n_[3]S=工(疋—刃20.11%n-iC—_0.11%cc«0/bx——吝-—1=—=0.055%Qna/43•当X=67.04时,u二—=67.04-66.62=2000.21当X=65.82时,U二―£=65.87—66.62=3600.21查口表P[65.87〜67.04]=0.4999+0.4773=97.72%出现在此区间可能的个数为(1-0.9772)xioo=2.28-2个
8、11・6-12.2
9、_02_
10、■杳P表
11、〃
12、=3的面积为0.4987分析结果小于11.6g/t概率P二0.5-0.4987=
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