Metastable de Sitter vacua from critical scalar theory

Metastable de Sitter vacua from critical scalar theory

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时间:2019-05-27

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1、MetastabledeSittervacuafromcriticalscalartheoryF.Loran∗andE.Bavarsad†DepartmentofPhysics,IsfahanUniversityofTechnology(IUT),Isfahan,IranStudyingthecriticalscalartheoryinfourdimensionalEuclideanspacewiththepotentialterm4−gφweshowthatthetheorycannotbeanalyticallycontinuedthroughg=0fromg

2、<0regiontog>0region.Forg>0althoughenergyisnotboundedfrombelowbutthereexistaclassicaltrajectorywithanAdS5modulispace,correspondingtoametastablelocalminimaoftheaction.ThefluctuationaroundthissolutionisgovernedbyaminimallycoupledscalartheoryonfourdimensionaldeSitterbackgroundwithareversed

3、Mexicanhatpotential.Sinceintheweakcouplinglimit,thepartitionfunctionpicksupcontributiononlyaroundclassicalsolutions,onecanassumethatourdeSitteruniversecorrespondstothatlocalminimawhichlifetimeincreasesexponentiallyasthecouplingconstanttendstozero.Similarresultsisobtainedinthecaseofcri

4、ticalscalartheorycoupledtoU(1)gaugefieldwhichisessentialforpeoplelivingonflatEuclideanspacetoobserveadeSitterbackgroundbyopticalinstruments.PACSnumbers:11.25.Hf,98.80.-k,04.62.+v,11.25.DbI.INTRODUCTIONRecently,weshowedthatthefluctuationsofthescalarfieldaroundtheclassicaltrajectoryofmassle

5、ssφ4modelinfourdimensionalflatEuclideanspacetimeisgovernedbyaconformallycoupledscalarfieldtheoryinfourdimensionaldeSitterbackground[1].Thisresultisinterestingduetoitsuniqueness.Infourdimensions,inprinciple,onecanconsidertwoclassesofcritical(classicallyscale-free)scalarfieldtheoriesi.e.ma

6、sslessφ4modelsonEuclidean(Minkowski)spacetimewithg,thecouplingconstant,eitherpositiveornegative(weassumethepotentialV(φ)=−gφ4).Althoughscalartheorywithg>0seemstobenotphysicalasenergyisnotboundedfrombelowbutas4isshownin[1]inthiscase,theEuler-LagrangeequationofmotionofthescalartheoryonE

7、uclideanspacehasaninterestingclassicalsolutionsayφwithfiniteactionS[φ]∼g−1.Interestingly,asfarasweareconsideringreal00scalarfieldtheoriesthemodelwiththephysicalpotentiali.e.thecaseofg<0hasnotsuchasolution,seeEq.(1).Weshouldclarifythatfromourpreviousviewpoint[1],forg<0,onecanstillconside

8、rasol

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