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1、.微机原理编程题1.分支程序设计①.编写一段程序，已知BUF1单元中有一带符号字节数据X，BUF2中有一带符号字节数据Y，根据以下函数关系编写程序求Z的值，结果存入RESULT单元。Z=
2、X-Y
3、；DATASEGMENTBUF1DB05HBUF2DB02HRESULTDB?DATAENDSCODESEGMENTASSUMECS:CODE,DS:DATASTART:MOVAX,DATAMOVDS,AXMOVAL,BUF1MOVBL,BUF2SUBAL,BLJNCGREATNEGALGREAT:MOVRESULT,ALEXIT:MOVAH,4CHINT2
4、1HCODEENDSENDSTART②.编写一段程序，已知BUF单元中有一无符号字节数据X，假设为8，根据以下函数关系编写程序求Y的值，结果存入RESULT单元。Z=5XX<10,X-5X>=10;DATASEGMENTBUFDB8RESULTDB?DATAENDSCODESEGMENTASSUMECS:CODE,DS:DATASTART:MOVAX,DATAMOVDS,AXMOVAL,BUFCMPAL,10JAEGREMOVBL,AL..ADDAL,ALADDAL,ALADDAL,BLJMPDONEGRE:SUBAL,5DONE:MOVRESULT
5、,ALMOVAH,4CHINT21HCODEENDSENDSTART③.在内存单元BUF中存放一个带符号字节数据X，假定为-2，试根据以下函数关系编写程序求Y的值，结果存入RESULT单元。Y=1X>0,0X=0,-1X<0;DATASEGMENTBUFDB-2RESULTDB?DATAENDSCODESEGMENTASSUMECS:CODE,DS:DATASTART:MOVAX,DATAMOVDS,AXMOVAL,BUFCMPAL,0JGEL1MOVAL,-1JMPL3L1:JZL2MOVAL,1JMPL3L2:MOVAL,0L3:MOVRESUL
6、T,ALMOVAH,4CHINT21HCODEENDSENDSTART1.N个数中求最大值、最小值.假定N=10,已知原始数据存放在BUF开始的内存单元中，将结果存入MAX，MIN内存单元中。DATASEGMENTBUFDB3,5,7,8,5,3,9,7,13,1COUNTEQU$-BUF..MAXDB?MINDB?DATAENDSCODESEGMENTASSUMECS:CODE,DS:DATASTART:MOVAX,DATAMOVDS,AXMOVCX,COUNT-1MOVAL,BUFMOVMAX,ALMOVMIN,ALLEASI,BUFAGAIN:
7、MOVAL,[SI+1]CMPAL,MINJGES1MOVMIN,ALS1:CMPAL,MAXJLES2MOVMAX,ALS2:INCSILOOPAGAINMOVAH,4CHINT21HCODEENDSENDSTART1.编写程序求1+2+3+……+N<100时最大的N值，将N值送NUM单元中，同时将1+2+3+……+N的和送到SUM单元中。DATASEGMENTNUMDB?SUMDB?DATAENDSCODESEGMENTASSUMECS:CODE,DS:DATASTART:MOVAX,DATAMOVDS,AXMOVAL,0MOVBL,0AGAIN
8、:INCBLADDAL,BL..CMPAL,100JBAGAINSUBAL,BLDECBLMOVNUM,BLMOVSUM,ALMOVAH,4CHINT21HCODEENDSENDSTART1.统计字符，正数，负数，零的个数。①．若自STRING单元开始存放一个字符串，以'$'结尾，试编写程序，统计字符串的长度，并将结果存入COUNT单元。DATASEGMENTSTRINGDB'abcdefg$'COUNTDW?DATAENDSCODESEGMENTASSUMECS:CODE,DS:DATASTART:MOVAX,DATAMOVDS,AXLEASI,S
9、TRINGMOVCX,0NEXT:MOVAL,[SI]CMPAL,'$'JZDONEINCCXINCSIJMPNEXTDONE:MOVCOUNT,CXMOVAH,4CHINT21HCODEENDSENDSTART②.自BUF单元开始存放10个带符号字节数据，将其中的正数、负数和零选出来，并统计其个数，分别存入PLUS、MINUS和ZERO单元中。DATASEGMENTBUFDB5,-2,0,-1,4,0,-4,8,0,-7PLUSDB?MINUSDB?ZERODB?..DATAENDSCODESEGMENTASSUMECS:DATA,DS:DATAS
10、TART:MOVAX,DATAMOVDS,AXLEASI,BUFMOVCX,10AGAIN:MOVAL,[B
