欢迎来到天天文库
浏览记录
ID:32737092
大小:74.40 KB
页数:12页
时间:2019-02-15
《浙大java实验题答案08answer》由会员上传分享,免费在线阅读,更多相关内容在工程资料-天天文库。
1、实验8Method的使用1.程序填空题,不要改变与输入输出有关的语句。50001求1+1/2!+・・・・+1/n!输入一个正整数repeat(02、taticvoidinain(String[]args){intri,repeat;inti,n;doubles;Scannerin=newScanner(System,in);repeat二in.nextlnt();for(ri=l;ri<=repeat;ri++){n二in.ncxtlnt();s=0;for(i=l;i<=n;i++)s+=l・0/«fact(i);System,out.printin((long)(s*10000+0・5)/10000.);}}/**/staticdoublefact(intn){in3、ti;doublef=l;for(i=l;i<=n;i++)f*=i;returnf;50002求a+aa+aaa+aa<4、8888+88888)importjava.util.Scanner;publicclassTest50002{publicstaticvoidmain(Stringargs[]){intri,repeat;inti,n,a;longsn;Scannerin二newScanner(System,in);repeat二in.nextlnt();for(ri=l;ri〈二repeat;ri++){a二in.nextlnt();npin.ncxtlnt();/**/sn=0;for(i=l;i<=n;i++)sn+=fn(a,i)5、;System,out.println(sn);}}/**/staticintfn(intazintn){ints=0;for(inti=l;i<=n;i++)s=s*10+a;returns;50003统计一个整数中数字的个数输入一个正整数repeat(06、:括号内是说明输入:3(repeat二3)-219022345543输出:count二2(-21902中有2个2)count=l(有1个2)count=0(345543中没有2)importjava,uti1.Scanner;publicclassTest50003{publicstaticvoidmain(Stringargs[]){intri,repeat;intcount;longn;Searrnerin二newSearmer(System,in);repeat二in.nextlnt();for(ri=l;ri<=re7、peat;ri++){n二in.nextlnt();/**/n=Math•abs(n);count=countdigit(n,2);System,out.printin("count二〃+count);}}/**/staticintcountdigit(longnumber,intdigit){//统计整数number中数字digit的个数inta,c=0;while(number>0){a=(int)(number%10);if(a==digit)c++;niiinber=nuinber/10;}returnc;}50008、4判断素数输入一个正整数repeat(0
2、taticvoidinain(String[]args){intri,repeat;inti,n;doubles;Scannerin=newScanner(System,in);repeat二in.nextlnt();for(ri=l;ri<=repeat;ri++){n二in.ncxtlnt();s=0;for(i=l;i<=n;i++)s+=l・0/«fact(i);System,out.printin((long)(s*10000+0・5)/10000.);}}/**/staticdoublefact(intn){in
3、ti;doublef=l;for(i=l;i<=n;i++)f*=i;returnf;50002求a+aa+aaa+aa<4、8888+88888)importjava.util.Scanner;publicclassTest50002{publicstaticvoidmain(Stringargs[]){intri,repeat;inti,n,a;longsn;Scannerin二newScanner(System,in);repeat二in.nextlnt();for(ri=l;ri〈二repeat;ri++){a二in.nextlnt();npin.ncxtlnt();/**/sn=0;for(i=l;i<=n;i++)sn+=fn(a,i)5、;System,out.println(sn);}}/**/staticintfn(intazintn){ints=0;for(inti=l;i<=n;i++)s=s*10+a;returns;50003统计一个整数中数字的个数输入一个正整数repeat(06、:括号内是说明输入:3(repeat二3)-219022345543输出:count二2(-21902中有2个2)count=l(有1个2)count=0(345543中没有2)importjava,uti1.Scanner;publicclassTest50003{publicstaticvoidmain(Stringargs[]){intri,repeat;intcount;longn;Searrnerin二newSearmer(System,in);repeat二in.nextlnt();for(ri=l;ri<=re7、peat;ri++){n二in.nextlnt();/**/n=Math•abs(n);count=countdigit(n,2);System,out.printin("count二〃+count);}}/**/staticintcountdigit(longnumber,intdigit){//统计整数number中数字digit的个数inta,c=0;while(number>0){a=(int)(number%10);if(a==digit)c++;niiinber=nuinber/10;}returnc;}50008、4判断素数输入一个正整数repeat(0
4、8888+88888)importjava.util.Scanner;publicclassTest50002{publicstaticvoidmain(Stringargs[]){intri,repeat;inti,n,a;longsn;Scannerin二newScanner(System,in);repeat二in.nextlnt();for(ri=l;ri〈二repeat;ri++){a二in.nextlnt();npin.ncxtlnt();/**/sn=0;for(i=l;i<=n;i++)sn+=fn(a,i)
5、;System,out.println(sn);}}/**/staticintfn(intazintn){ints=0;for(inti=l;i<=n;i++)s=s*10+a;returns;50003统计一个整数中数字的个数输入一个正整数repeat(06、:括号内是说明输入:3(repeat二3)-219022345543输出:count二2(-21902中有2个2)count=l(有1个2)count=0(345543中没有2)importjava,uti1.Scanner;publicclassTest50003{publicstaticvoidmain(Stringargs[]){intri,repeat;intcount;longn;Searrnerin二newSearmer(System,in);repeat二in.nextlnt();for(ri=l;ri<=re7、peat;ri++){n二in.nextlnt();/**/n=Math•abs(n);count=countdigit(n,2);System,out.printin("count二〃+count);}}/**/staticintcountdigit(longnumber,intdigit){//统计整数number中数字digit的个数inta,c=0;while(number>0){a=(int)(number%10);if(a==digit)c++;niiinber=nuinber/10;}returnc;}50008、4判断素数输入一个正整数repeat(0
6、:括号内是说明输入:3(repeat二3)-219022345543输出:count二2(-21902中有2个2)count=l(有1个2)count=0(345543中没有2)importjava,uti1.Scanner;publicclassTest50003{publicstaticvoidmain(Stringargs[]){intri,repeat;intcount;longn;Searrnerin二newSearmer(System,in);repeat二in.nextlnt();for(ri=l;ri<=re
7、peat;ri++){n二in.nextlnt();/**/n=Math•abs(n);count=countdigit(n,2);System,out.printin("count二〃+count);}}/**/staticintcountdigit(longnumber,intdigit){//统计整数number中数字digit的个数inta,c=0;while(number>0){a=(int)(number%10);if(a==digit)c++;niiinber=nuinber/10;}returnc;}5000
8、4判断素数输入一个正整数repeat(0
此文档下载收益归作者所有