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时间:2018-09-04
《32汇编前5章习题参考答案》由会员上传分享,免费在线阅读,更多相关内容在行业资料-天天文库。
1、习题参考答案习题11、(1)FFH=11111111B=255D(2)0H=0000B=0D(3)F3E1H=1111001111100001B=62433D(4)B64AH=1011011001001010B=46666D(5)2EH=00101110B=46D(6)10H=00010000B=16D(7)1FH=00011111B=31D(8)ABH=10101011B=171D2、(1)12=00010010(2)24=00100100(3)68=01101000(4)127=000100100111(5)128=000100101000(6)25
2、5=001001010101(7)1234=0001001000110100(8)2458=00100100010110003、(1)10101101B=ADH(2)1001101001B=269H(3)10B=2H(4)11110B=1EH(5)111110B=3EH(6)0101011101B=15DH(7)110100101B=1A5H(8)10000101B=85H4、(1)10010001=91D(2)10001001=89D(3)00110110=36D(4)10010000=90D(5)00001000=8D(6)10010111=97D(
3、7)10000001=81D(8)00000010=2D5、(1)0=[000000000]原=[000000000]反=[000000000]补(2)-127=[111111111]原=[100000000]反=[100000000]补(3)127=[011111111]原=[011111111]反=[011111111]补(4)-57=[100111001]原=[111000110]反=[111000111]补(5)126=[011111110]原=[011111110]反=[011111110]补(6)-126=[111111110]原=[1000
4、00001]反=[100000010]补(7)-128=[100000000]补,无原码和反码(8)11947超出8位二进制表示范围,无原、反、补码6、(1)-1=[10000000000000001]原=[11111111111111110]反=[11111111111111111]补(2)-10=[10000000000001010]原=[11111111111110101]反=[11111111111110110]补(3)845=[00000001101001101]原=[00000001101001101]反=[00000001101001101
5、]补(4)-923=[10000001110011011]原=[11111110001100100]反=[11111110001100101]补(5)100=[00000000001100100]原=[00000000001100100]反=[00000000001100100]补(6)15000=[00011101010011000]原=[00011101010011000]反=[00011101010011000]补7、(1)-1=[100000000000000000000000000000001]原=[1111111111111111111111
6、11111111110]反=[111111111111111111111111111111111]补(2)-10=[100000000000000000000000000001010]原=[111111111111111111111111111110101]反=[111111111111111111111111111110110]补(3)23=[000000000000000000000000000010111]原=[000000000000000000000000000010111]反=[00000000000000000000000000001011
7、1]补(4)-100=[100000000000000000000000001100100]原=[111111111111111111111111110011011]反=[111111111111111111111111110011100]补8、(1)B64AH=1011011001001010B=-13898D(2)F3E1H=1111001111100001B=-29665D(3)6F20H=0110111100100000B=28448D(4)00E1H=0000000011100001B=225D9、(1)1000B64AH=0001000000
8、0000001011011001001010B=268482122D(2)98C
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